Bourbaki

Exercise 18, § 5

Tag 037T, permanent. Cite it as [Bourbaki, Tag 037T].

Spectral Theories, IV, p. 358

Bourbaki marks this one as harder than the rest.

Let nn be an integer ⩾1\geqslant 1. Let D denote the partial operator on L2(Tn)L^2(\mathbf{T}^n) with domain C∞(Tn)\mathscr{C}^{\infty}(\mathbf{T}^n) such that

D(φ)=−∑i=1n∂i2φ D(\varphi ) =-\sum_{i=1}^n\partial_i^2\varphi

for every φ∈C∞(Tn)\varphi \in \mathscr{C}^{\infty}(\mathbf{T}^n),

a) The partial operator D is essentially self-adjoint. Let Δ denote its closure.

b) The partial operator Δ is self-adjoint and positive.

c) The partial operator Δ has compact resolvent.

d) Let λ∈R\lambda \in \mathbf{R}. One has λ∈\lambda \in Sp(Δ) if and only if there exist natural integers k1,...,knk_1, . . .,k_n such that λ=4π2(k12+⋯+kn2)\lambda = 4\pi^2(k^2_1+\cdots +k^2_n).

e) For every eigenvalue λ\lambda of Δ, let N(λ)N(\lambda ) be the dimension of the corresponding eigenspace. One has

∑λ⩽TN(λ)=cnTn/2+O(T(n−1)/2) \sum_{\lambda\leqslant T}N(\lambda ) =c_nT^{n/2}+ O(T^{(n-1)/2})

when T→+∞T\rightarrow +\infty.

f) If n⩾2n\geqslant 2, then lim supλN(λ)=+∞_{\lambda}N(\lambda ) = +\infty. (In the case n=2n= 2, consider λ=4π2m\lambda = 4\pi^2m, where mm is a product of prime numbers of the form 4k+1.4k+ 1.) g) If n=1n= 1 or n=2n= 2, one has

Card(Sp(uu)∩[0,T]\cap [0,T]) =o(T)=o(T),

and if n⩾3n\geqslant 3, one has

lim infT→+∞1T_{T\rightarrow+\infty}\frac{1}{T} Card(Sp(uu)∩[0,T]\cap [0,T])>0>0.

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Machine translation of the English, by gpt-5.4. Not checked by a person.