Bourbaki

Exercise 21, § 5

Tag 037W, permanent. Cite it as [Bourbaki, Tag 037W].

Spectral Theories, IV, p. 359

Let xx denote the identity function of R\mathbf{R}. Let Mm(R)\mathscr{M}_m(\mathbf{R}) denote the set of positive measures ν\nu on R\mathbf{R} such that xn∈L1(R,ν)x^n\in \mathscr{L}^1(\mathbf{R}, \nu ) for every integer n∈Nn\in \mathbf{N}. a) Let ν∈Mm(R)\nu \in \mathscr{M}_m(\mathbf{R}) and put μn=ν(xn)\mu_n=\nu (x^n) for every n∈Nn\in \mathbf{N} ("moments of the measure ν\nu"). For every integer n⩾0n\geqslant 0 and for every complex numbers a0,...,ana_0, . . . , a_n, one has

∑i=0n∑j=0na‾iajμi+j⩾0(24) \sum_{i=0}^n\sum_{j=0}^n\overline{a}_ia_j\mu_{i+j}\geqslant 0 \tag{24}

In what follows, we propose to study the converse assertion to question a) ("Hamburger moment problem"). In the rest of this exercise, we therefore suppose given a sequence μ=(μn)n⩾0\boldsymbol{\mu}= (\mu_n)_{n\geqslant 0} of real numbers satisfying condition (24). b) There exists a unique positive sesquilinear form bμb_{\boldsymbol{\mu}} on C[X]\mathbf{C}[X] such that bμ(Xi,Xj)=μi+jb_{\boldsymbol{\mu}}(X^i,X^j) =\mu_{i+j} for all integers ii and jj.

Let EμE_{\boldsymbol{\mu}} denote the separated completion Hilbert space of C[X]\mathbf{C}[X] for the form bμb_{\boldsymbol{\mu}}. c) The linear mapping uμu_{\boldsymbol{\mu}} of C[X]\mathbf{C}[X] into C[X]\mathbf{C}[X] defined by uμ(P)=u_{\boldsymbol{\mu}}(P) = XP induces, by passing to the quotient, a symmetric partial operator uμu_{\boldsymbol{\mu}} on the Hilbert space EμE_{\boldsymbol{\mu}}.

d) The partial operator uμu_{\boldsymbol{\mu}} admits a self-adjoint extension.

e) There exists a measure ν∈Mm(R)\nu \in \mathscr{M}_m(\mathbf{R}) such that μn=ν(xn)\mu_n=\nu (x^n) for every n∈Nn\in \mathbf{N}. f) The sesquilinear form bμb_{\boldsymbol{\mu}} is separated if and only if, for every measure ν∈Mm(R)\nu \in \mathscr{M}_m(\mathbf{R}) such that μn=ν(xn)\mu_n=\nu (x^n) for every n∈Nn\in \mathbf{N}, the support of ν\nu is infinite. (Observe that the left-hand side of inequality (24) is equal to bμ(p,p)b_\mu(p, p) for p=a0+⋯+anXn.p=a_0+\cdots +a_nX^n.)

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Machine translation of the English, by gpt-5.4. Not checked by a person.