Spectral Theories, IV, p. 364
Let M=X2Y2(X2+Y2−3)∈R[X,Y] ("Motzkin polynomial"). (a) One has M(x,y)⩾0 for all x and y in R.
(b) There exists no finite family (pi)i∈I in R[X,Y] such that M=∑pi2. (If such a family existed, now prove that each pi must be of the form a+bXY with a∈R and b∈R[X,Y] of degree at most 1; then calculate the coefficient of (XY)2.)
(c) Let τ:N2→N−{0} be the mapping defined by
τ(0,0)=1,τ(1,2)=2,τ(2,1)=3,τ(1,1)=4,τ(1,0)=5
τ(0,1)=6,τ(2,0)=7,τ(0,2)=8,τ(3,0)=9,τ(0,3)=10
and
τ(i,j)=j+1+(i+j)(i+j+1)/2 if i+j⩾4.
The mapping τ is a bijection.
(d) Let (νn)n⩾1 be the sequence defined by
νi=1 if i∈{1,2,3},ν4=4,νn=(n!)(n+1)! if n⩾5.
For n and m in N, put μn,m = 0 if n or m is odd and μn,m=ντ(n/2,m/2) otherwise. The linear mapping α of C[X,Y] into C such that α(XnYm)=μn,m satisfies α(p2)⩾0 for every p∈R[X,Y]. (It is enough to verify that, for every integer k∈N, the determinant of the matrix (am,m)1⩽n,m⩽k is positive, where an,m is defined by aτ(i,j),τ(i′,j′)=α(Xi+i′Yj+j′) for all (i,j,i′,j′); then proceed by induction on k.)
(e) There exists no positive measure ν on R2 such that (x,y)↦xnym is μ-integrable for all (n,m)∈N2, and such that
∫R2xnymdν(x,y)=μn,m
for all (n,m)∈N2. (f) There exist a Hilbert space E and a partial operator u with dense domain on E satisfying the following conditions:
(i) One has dom(u)⊂ dom(u∗);
(ii) One has ∥u(x)∥=∥u∗(x)∥ for every x∈ dom(u);
(iii) There exist no Hilbert space F containing E as a subspace, such that the canonical injection of E into F is isometric, and no normal partial operator v on F such that u⊂v.
Compare this result with exercise 24 of IV, p. 352.
Nothing.
Nothing.