Bourbaki

Exercise 33, § 5

Tag 0388, permanent. Cite it as [Bourbaki, Tag 0388].

Spectral Theories, IV, p. 368

Let n∈Nn\in \mathbf{N}. We denote by Δ the Laplacian on L2(Rn)L^2(\mathbf{R}^n).

a) For every t∈R∗t\in \mathbf{R}^*, the endomorphism eitΔe^{it\Delta} of L2(Rn)L^2(\mathbf{R}^n) is given by

eitΔf(x)=1(2it)n/2∫Rnf(y)ei∣x−y∣2/(4t)dy e^{it\Delta}f(x) =\frac{1}{(2it)^{n/2}}\int_{\mathbf{R}^n}f(y)e^{i|x-y|^2/(4t)}dy

if f∈L1(Rn)∩L2(Rn)f\in \mathscr{L}^1(\mathbf{R}^n)\cap \mathscr{L}^2(\mathbf{R}^n). (Use the Fourier transform.)

b) Let C be the unitary mapping on L2(Rn)L^2(\mathbf{R}^n) deduced by passing to the quotient from the mapping f↦C(f)f\mapsto C(f) defined for f∈L2(Rn)f\in \mathscr{L}^2(\mathbf{R}^n) by

C(f)(x)=1(2it)n/2eix24tFf(x2t) C(f)(x) =\frac{1}{(2it)^{n/2}}e\frac{ix^2}{4t}\mathscr{F}f(\frac{x}{2t})

for x∈Rnx\in \mathbf{R}^n.

One has eitΔ→Ce^{it\Delta}\rightarrow C when t→+∞t\rightarrow +\infty in the space L(L2(Rn))\mathscr{L}(L^2(\mathbf{R}^n)) endowed with the topology of simple convergence.

c) Suppose that 1⩽n⩽31\leqslant n\leqslant 3. Let g∈L∞(Rn)+L2(Rn)g\in \mathscr{L}^{\infty}(\mathbf{R}^n) +\mathscr{L}^2(\mathbf{R}^n) be real-valued. Let us denote by uu the partial operator u=Δ+mgu= \Delta +m_g; it is self-adjoint on L2(Rn)L^2(\mathbf{R}^n) (exercise 14). For f∈L1(Rn)∩L2(Rn)f\in \mathscr{L}^1(\mathbf{R}^n)\cap \mathscr{L}^2(\mathbf{R}^n) and t∈R∗t\in \mathbf{R}^*, one has

eituf(x)=e^{itu}f(x) = limk→+∞1(2it/k)kn/2∫Rnkf(yk)_{k\rightarrow+\infty}\frac{1}{(2it/k)^{kn/2}}\int_{\mathbf{R}^{nk}}f(y_k) exp(itk∑i=1k(∣yi−yi−1∣24(t/k)2−g(yi))dy(\frac{it}{k}\sum_{i=1}^k(\frac{|y_i-y_{i-1}|^2}{4(t/k)^2}-g(y_i))dy

where one writes y=(y1,...,yk)y= (y_1, . . . , y_k) with yi∈Rny_i\in \mathbf{R}^n.

d) Interpretation of the preceding formula.

Solution

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Cites

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Machine translation of the English, by gpt-5.4. Not checked by a person.