Bourbaki

Exercise 40, § 5

Tag 038F, permanent. Cite it as [Bourbaki, Tag 038F].

Spectral Theories, IV, p. 370

Let E be a complex Hilbert space.

a) Let uu be a normal partial operator on E and let (j,∣u∣)(j,|u|) be its polar decomposition. One has ∣u∗∣=∣u∣|u^*|=|u| and the polar decomposition of u∗u^* is (j∗,∣u∣)(j^*,|u|). One has j∣u∣=∣u∣jj|u|=|u|j.

b) Let uu be a self-adjoint partial operator on E and let (j,∣u∣)(j,|u|) be its polar decomposition. One has j=j= s(uu), where the function s is defined by

1 if x>0x >0

s(xx) == 0 if x=0x= 0

−1-1 if x<0x <0.

c) Let uu be a self-adjoint partial operator on E and let (j,∣u∣)(j,|u|) be its polar decomposition. Let D denote the domain of ∣u∣1/2|u|^{1/2}, and define a partial Hermitian form qq with domain D by putting

q(x,y)=⟨∣u∣1/2(x)∣j∣u∣1/2(y)⟩ q(x, y) =\langle |u|^{1/2}(x)|j|u|^{1/2}(y)\rangle

The partial operator representing qq coincides with uu; if uu is positive, then qq is the positive partial form associated with uu.

d) Let uu and vv be self-adjoint partial operators on E. Let quq_u and qvq_v denote the partial Hermitian forms defined as in question c). Suppose that dom(quq_u)∩\cap dom(qvq_v) is dense in E. The sum of uu and vv in the sense of Hermitian forms is the partial operator uu + vv on E representing the partial form

q(x,y)=qu(x,y)+qv(x,y) q(x, y) =q_u(x, y) +q_v(x, y)

with domain dom(quq_u)∩\cap dom(qvq_v). Now prove that the partial operator uu+ vv is an extension of u+vu+v; if uu and vv are positive, then uu+ vv is a positive self-adjoint partial operator.

e) Give an example where the domain of u+vu+v is not dense, but uu + vv is defined.

f ) Let n⩾1n\geqslant 1 be an integer and S⊂RnS\subset \mathbf{R}^n a closed set of Lebesgue measure zero. Let vv be a positive measurable function on Rn\mathbf{R}^n for the Lebesgue measure such that vv is locally integrable on Rn−\mathbf{R}^n- S. The self-adjoint partial operator Δ + mvm_v is defined.

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Machine translation of the English, by gpt-5.4. Not checked by a person.