Let π and ϱ be unitary representations of a topological group G in Hilbert spaces E and F respectively. Let D be a dense subspace of E which is stable under π. Let u be a closed partial operator from E into F with domain D such that u∘π(g)=ϱ(g)∘u for every g∈G. Then the domain of u∗ is stable under ϱ and one has the relation u∗∘ϱ(g)=π(g)∘u∗ for every g∈G.
Let g∈G and x∈ dom(u∗). For every y∈ dom(u), one has
⟨ϱ(g)x∣u(y)⟩=⟨x∣ϱ(g−1)u(y)⟩=⟨x∣u(π(g−1)y)⟩
=⟨u∗(x)∣π(g−1)y⟩=⟨π(g)(u∗(x))∣y⟩
since ϱ(g)∗=ϱ(g)−1=ϱ(g−1). This proves that ϱ(g)x∈ dom(u∗) and that u∗(ϱ(g)x)=π(g)(u∗(x)). In particular, the domain of u∗∘ϱ(g) contains the domain of u∗, and π(g)∘u∗⊂u∗∘ϱ(g).
But moreover, if x∈ dom(u∗∘ϱ(g)), then x=ϱ(g−1)(ϱ(g)x) belongs to dom(u∗) by what precedes applied to g−1. It follows that u∗∘ϱ(g)=π(g)∘u∗.
Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.