Bourbaki

Lemma 3

Tag 03AC, permanent. Cite it as [Bourbaki, Tag 03AC].

Théories spectrales, chapter V, § 2. Représentations des groupes localement compacts

Let pp be a real number ⩾1\geqslant 1. The left (resp. right) regular representation of G in Lp(G,μ)(L^p(G, \mu) (resp. in Lp(G,μ′))L^p(G, \mu')) is faithful.

More precisely, let qq be the conjugate exponent of pp and let gg be an element of G such that g≠eg\not =e.

a) There exists a function φ∈K(G)\varphi \in \mathscr{K}(G), positive and nonzero in Lq(G,μ)L^q(G, \mu), such that ⟨φ,γG(p)(g)φ⟩=0\langle \varphi ,\boldsymbol{\gamma }^{(p)}_G(g)\varphi \rangle = 0;

b) There exists a function φ∈K(G)\varphi \in \mathscr{K}(G), positive and nonzero in Lq(G,μ′)L^q(G, \mu'), such that ⟨φ,δG(p)(g)φ⟩=0\langle \varphi ,\boldsymbol{\delta }^{(p)}_G(g)\varphi \rangle = 0.

Let us consider the case of the left regular representation γG(p)\boldsymbol{\gamma }^{(p)}_G, that of the right regular representation being similar. Assertion a) implies that γG(p)\boldsymbol{\gamma }^{(p)}_G is faithful, for if g≠eg\not =e is an element of G, and if φ\varphi is as in a), one has φ≠γG(p)(g)φ\varphi \not =\boldsymbol{\gamma }^{(p)}_G(g)\varphi since ⟨φ,φ⟩=∫Gφ2>0\langle \varphi , \varphi \rangle =\int_G\varphi^2>0.

Let us therefore prove a). Let g≠eg\not =e in G. Let C be a symmetric compact neighbourhood of ee such that g∉C2g \notin C^2 and let φ∈K(G)\varphi \in \mathscr{K}(G) be a positive continuous function of integral 1 with support contained in C; the function φ\varphi is nonzero in Lp(G,μ)L^p(G, \mu). Since C∩g−1C=∅C\cap g^{-1}C =\emptyset, one has

⟨φ,γG(p)(g)φ⟩=∫Gφ(x)φ(g−1x)dμ(x)=0 \langle \varphi ,\boldsymbol{\gamma }^{(p)}_G(g)\varphi \rangle =\int_G\varphi (x)\varphi (g^{-1}x)d\mu(x) = 0

Let ϱ\varrho be a continuous bounded representation of G in a Banach space E. For every f∈L1(G)f\in L^1(G) (resp. f′∈L1(G,μ′)f'\in L^1(G, \mu')) and every g∈Gg\in G, one has

(1) ϱ(g)ϱ(f⋅μ)=ϱ(εg∗(f⋅μ))=ϱ(γG(1)(g)f⋅μ)\varrho (g)\varrho (f\cdot \mu) =\varrho (\varepsilon_g*(f\cdot \mu)) =\varrho (\boldsymbol{\gamma }^{(1)}_G(g)f\cdot \mu),

(2) ϱ(f′⋅μ′)ϱ(g)=ϱ((f′⋅μ′)∗εg)=ϱ(δG(1)(g−1)f′⋅μ′)\varrho (f'\cdot \mu')\varrho (g) =\varrho ((f'\cdot \mu')*\varepsilon_g) =\varrho (\boldsymbol{\delta }^{(1)}_G(g^{-1})f'\cdot \mu')

(INT, VIII, p. 144, § 3, no2^o2, formula (5)).

Suppose G unimodular, and put μ′=μ\mu'=\mu. The biregular representation of G in Lp(G)\mathscr{L}^p(G) (resp. in Lp(G)L^p(G)) is the representation ϱG(p)\boldsymbol{\varrho }^{(p)}_G of G×GG\times G in Lp(G)\mathscr{L}^p(G) (resp. in Lp(G)L^p(G)) such that

ϱG(p)(g1,g2)=γG(p)(g1)δG(p)(g2)=δG(p)(g2)γG(p)(g1) \boldsymbol{\varrho }_G^{(p)}(g_1, g_2) =\boldsymbol{\gamma }_G^{(p)}(g_1)\boldsymbol{\delta }_G^{(p)}(g_2) =\boldsymbol{\delta }_G^{(p)}(g_2)\boldsymbol{\gamma }_G^{(p)}(g_1)

It is a continuous linear representation (Lemma 1 of V, p. 377). It satisfies

(ϱG(p)(g1,g2)f)(x)=f(g1−1xg2) (\boldsymbol{\varrho }_G^{(p)}(g_1, g_2)f)(x) =f(g_1^{-1}xg_2)

for every f∈Lpf\in \mathscr{L}^p(G), every (g1,g2)∈G×G(g_1, g_2)\in G\times G and every x∈Gx\in G.

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

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Cites

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Machine translation of the English, by gpt-5.4, gpt-5-6-mini, against glossary version 34. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.