and since (y↦η(g−1,y))⋅ν=γG/H(g)ν, one obtains Np(f)=Np(f).
It follows from this lemma that there exists a continuous isometric representation π of G in Lπp(G) such that for f∈Kπ(G) and g∈G, the element π(g)f is the class of the function f defined above. If p=2, then this representation is unitary.
Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.