There exists a real number c>0 such that the linear mapping w=c1/2v is isometric.
This lemma being assumed valid, let us remark that formula (10), p. 420, may be written
v(π(g1)x⊗π(h1)y)=ϱG,χ(g1,h1)v(x⊗y)(11)
for all (g1,h1)∈G×G and all (x,y)∈E×E. The isometric linear mapping w of E⊗E into Lχ2(G) admits a continuous extension, still denoted by w, to E⊗2E. By continuity and linearity, formula (11) implies that w is a (G× G)-morphism of π⊠π into Lχ2(G), which concludes the proof of the proposition.
Let us prove the lemma. For every x∈E, let ux denote the linear mapping y↦v(x⊗y)=fx,y of E into Lχ2(G). We have ux∈ HomG(π,γG,χ) (formula (10)). By cor. 5 of V, p. 388, there exists a real number λx⩾0 such that λxux is isometric.
This means that the positive real number λx/∥x∥2 is independent of the choice of the nonzero element x of E. It is strictly positive since, for every nonzero x, the function fx,x is continuous and takes the value ∥x∥2>0 at e, whence ∥ux(x)∥=∥fx,x∥>0. Let us denote this real number by c−1.
For every (x,y)∈E×E, it follows that
∥v(x⊗y)∥2=∥fx,y∥2=λx∥y∥2=c−1∥x∥2∥y∥2=c−1∥x⊗y∥2
Using EVT, V, p. 29, cor. 1, we deduce that the linear mapping w=c1/2v of E⊗2E into Lχ2(G) is isometric, as required.
Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.