Bourbaki

Exercise 6, § 2

Tag 03BI, permanent. Cite it as [Bourbaki, Tag 03BI].

Spectral Theories, V, p. 487

One assumes that the group G is unimodular. We denote by G^d⊂G^\widehat{G}_d\subset \widehat{G} the set of classes of irreducible unitary square integrable representations of G. For π∈G^d\pi \in \widehat{G}_d, we denote by pπp_{\pi} the orthogonal projector of L2(G)L^2(G) whose image is the π\pi-isotypical component of the right regular representation of G.

(a) Let f∈L2(G)f\in \mathscr{L}^2(G) and let π∈G^d\pi \in \widehat{G}_d. We denote by E the space of π\pi. The mapping g↦f(g)π(g)g\mapsto f(g)\pi (g) belongs to L1(G;L(E))L^1(G;\mathscr{L}(E)); the endomorphism

v=∫Gf(g)π(g)dμ(g) v=\int_Gf(g)\pi (g)d\mu(g)

is a Hilbert–Schmidt endomorphism, denoted v=π(f)v=\pi (f).

(b) Let f∈L2(G)f\in \mathscr{L}^2(G). We have ∥π(f‾)∥2=∥pπ(f)∥\|\pi (\overline{f})\|_2=\|p_{\pi}(f)\|.

(c) Let Ld2(G)L^2_d(G) be the closed subspace of L2(G)L^2(G) generated by the π\pi-isotypical components of L2(G)L^2(G) for π∈G^d\pi \in \widehat{G}_d. It is the Hilbertian sum of the images of the orthogonal projectors pπp_{\pi} for π∈G^d\pi \in \widehat{G}_d. For every f∈Ld2f\in L^2_d(G), one has

∥f∥2=∑π∈G^dc(π)∥π(f)∥22 \|f\|^2=\sum_{\pi\in\widehat{G}_d}c(\pi )\|\pi (f)\|^2_2

where c(π)c(\pi ) is the formal degree of π\pi relative to {e}\{e\}.

Solution

No solution has been written yet.

Cited by

Nothing.

Cites

Nothing.

Machine translation of the English, by gpt-5-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.