Bourbaki

Exercise 16, § 2

Tag 03BS, permanent. Cite it as [Bourbaki, Tag 03BS].

Spectral Theories, V, p. 490

Let G=SL(2,R)G =\mathbf{S}\mathbf{L}(2,\mathbf{R}) and let H\mathbf{H} denote the open subset of C\mathbf{C} consisting of the complex numbers zz such that I(z)>0\mathscr{I}(z)>0. Let μ\mu denote the Lebesgue measure on C\mathbf{C}. For every element

(ab) (a b)
g= g=
cd c d

of G and every z∈Hz\in \mathbf{H}, put j(g,z)=cz+dj(g, z) =cz+d.

a) The group G acts continuously on the left on H\mathbf{H} by

(abcd)⋅z=az+bcz+d (a bc d)\cdot z=\frac{az + b}{cz + d}

The measure ν=y−2⋅μ\nu =y^{-2}\cdot \mu is G-invariant.

b) Let nn be an integer such that n⩾2n\geqslant 2. Let EnE_n denote the vector space of holomorphic functions f:H→Cf:\mathbf{H}\rightarrow \mathbf{C} such that the function z↦∣f(z)∣2I(z)nz\mapsto |f(z)|^2\mathscr{I}(z)^n belongs to L2(H,ν)\mathscr{L}^2(\mathbf{H}, \nu ). The space EnE_n endowed with the sesquilinear form

⟨f∣g⟩=∫Hf(z)‾g(z)I(z)ndν(z) \langle f|g\rangle =\int_{\mathbf{H}}\overline{f(z)}g(z)\mathscr{I}(z)^nd\nu (z)

is a Hilbert space of countable type and of infinite dimension.

c) For every g∈Gg\in G and every f∈Enf\in E_n, put

πn(g)f(z)=j(g−1,z)−nf(g−1⋅z) \pi_n(g)f(z) =j(g^{-1}, z)^{-n}f(g^{-1}\cdot z)

The mapping πn\pi_n defines a unitary representation of G in EnE_n.

d) The function fnf_n defined by fn(z)=(z+i)−nf_n(z) = (z+i)^{-n} belongs to EnE_n; it satisfies πn(k)fn=χ−n(k)fn\pi_n(k)f_n=\chi_{-n}(k)f_n for every k∈SO(R2)k\in \mathbf{S}\mathbf{O}(\mathbf{R}^2), where χn\chi_n is the character such that

(((( cos(θ\theta ) sin(θ\theta )))inθ_{in\theta}

χn=e \chi_n=e

−- sin(θ\theta ) cos(θ\theta )

for every θ∈R\theta \in \mathbf{R}.

e) Let F be a subrepresentation of EnE_n. The orthogonal projector of EnE_n whose image is the χ−n\chi_{-n} isotypical component of the restriction of πn\pi_n to SO(R2)\mathbf{S}\mathbf{O}(\mathbf{R}^2) is given by f↦−(2i)nf(i)fnf\mapsto -(2i)^nf(i)f_n. (Use Cor. 2 of V, p. 465 and the Cauchy integral formula, FVC, to appear.)

f) The representation πn\pi_n is irreducible.

g) The matrix coefficient g↦⟨fn∣πn(g)fn⟩g\mapsto \langle f_n|\pi_n(g)f_n\rangle is nonzero and belongs to L2(G)\mathscr{L}^2(G).

h) The representation πn\pi_n is square-integrable and there exists a constant c>0c >0 such that the formal degree of πn\pi_n is c(n−1)c(n-1).

Solution

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Machine translation of the English, by gpt-5.4. Not checked by a person.