Let π be an irreducible representation of G. The mapping f↦π(f) defines by passing to the subspaces an isometric isomorphism of ϱG(π) into End(Eπ).
Put επ(g,h)u=π(g)∘u∘π(h−1) for every (g,h)∈G×G and for every u∈ End(Eπ). The mapping επ is a continuous representation of G×G in End(Eπ). It is unitary. In fact, since π itself is unitary, one obtains
= dim(π ) Tr(π(h)u∗uπ(h)−1) = dim(π ) Tr(u∗u) =∥u∥22 for every (g,h)∈G×G and every u∈ End(Eπ).
The mapping Ψ defined by f↦π(f) is a (G× G)-morphism of ϱG(π) into End(Eπ), since
π(ϱG(g,h)f)=∫Gf(g−1xh)π(x)dμ(x)=π(g)π(f)π(h−1)
for every (g,h)∈G×G and every f∈ϱG(π). Since ϱG(π) is an irreducible representation (th. 1, a) of V, p. 462), there exists λ∈C∗ such that the mapping λΨ is zero or isometric (cor. 5, a) of V, p. 388).
Let f= dim(π )χπ∈ϱG(π). Then π(f)=1Eπ (cor. 2 of V, p. 465), whence ∥π(f)∥2= dim(π ) =∥f∥ (cor. 3 of V, p. 459). Consequently, the mapping Ψ is isometric. Since ϱG(π) and End(Eπ) are of the same dimension, Ψ is an isometric isomorphism.
We denote by F2(G) the Hilbert sum of the Hilbert spaces End(Eπ). The norm of an element x∈F2(G) is again denoted by ∥x∥2.
In LIE, IX, p. 79, this space is denoted L2(G), a notation which we prefer to avoid here so as not to create confusion with the space ℓ2(G).
Let (uπ) be an element of F2(G). Since
π∈G∑π∈G∥uπ∥22=∑π∈G dim(π ) Tr(uπ∗uπ)<+∞
and ∥uπ∥2⩽ Tr(uπ∗uπ) (cf. EVT, V, p. 52, formula (33)), the norm in L(Eπ) of the endomorphism uπ tends to 0 at infinity. One can therefore identify F2(G) with a subspace of F0(G).
Let π∈G and u∈ End(Eπ). We denote by Fπ(u) the function on G defined by Fπ(u)(g)=⟨π(g)∣u⟩= dim(π)Tr(π(g)∗u) for every g∈G. This is a continuous function on G. If G is a compact real Lie group, then the function Fπ(u) is analytic on G (LIE, III, § 8, no1, th. 1).
Since G is compact, one can identify L2(G) with a subspace of L1(G).
Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.