Bourbaki

Exercise 1, § 3

Tag 03G9, permanent. Cite it as [Bourbaki, Tag 03G9].

Theory of Sets, I, 57

Let AA, BB, CC be relations in a logical theory T\mathscr{T}. Show that the following relations are theorems in T\mathscr{T} :

A⇒(B⇒A),A \Rightarrow (B \Rightarrow A),
(A⇒B)⇒((B⇒C)⇒(A⇒C)),(A \Rightarrow B) \Rightarrow ((B \Rightarrow C) \Rightarrow (A \Rightarrow C)),
A⇒((not A)⇒B),A \Rightarrow ((\text{not } A) \Rightarrow B),
(A or B)⇔((A⇒B)⇒B),(A \text{ or } B) \Leftrightarrow ((A \Rightarrow B) \Rightarrow B),
(A⇔B)⇔((A and B) or ((not A) and (not B))),(A \Leftrightarrow B) \Leftrightarrow ((A \text{ and } B) \text{ or } ((\text{not } A) \text{ and } (\text{not } B))),
(A⇔B)⇔not ((not A)⇔B),(A \Leftrightarrow B) \Leftrightarrow \text{not } ((\text{not } A) \Leftrightarrow B),
(A⇒(B or (not C)))⇔((C and A)⇒B),(A \Rightarrow (B \text{ or } (\text{not } C))) \Leftrightarrow ((C \text{ and } A) \Rightarrow B),
(A⇒(B or C))⇔(B or (A⇒C)),(A \Rightarrow (B \text{ or } C)) \Leftrightarrow (B \text{ or } (A \Rightarrow C)),
(A⇒B)⇒((A⇒C)⇒(A⇒(B and C))),(A \Rightarrow B) \Rightarrow ((A \Rightarrow C) \Rightarrow (A \Rightarrow (B \text{ and } C))),
(A⇒C)⇒((B⇒C)⇒((A or B)⇒C)),(A \Rightarrow C) \Rightarrow ((B \Rightarrow C) \Rightarrow ((A \text{ or } B) \Rightarrow C)),
(A⇒B)⇒((A and C)⇒(B and C)),(A \Rightarrow B) \Rightarrow ((A \text{ and } C) \Rightarrow (B \text{ and } C)),
(A⇒B)⇒((A or C)⇒(B or C)).(A \Rightarrow B) \Rightarrow ((A \text{ or } C) \Rightarrow (B \text{ or } C)).
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Transcribed from the printed volume. Not translated.