Let ((Xλ,ι)ι∈Jλ)λ∈L be a family (with index set L) of families of sets. Let I=∏λ∈LJλ. Then
λ∈L∏(ι∈Jλ⋃Xλ,ι)=f∈I⋃(λ∈L∏Xλ,f(λ))
and (if L=∅ and Jλ=∅ for each λ∈L)
λ∈L∏(ι∈Jλ⋂Xλ,ι)=f∈I⋂(λ∈L∏Xλ,f(λ))
("distributivity" of product over union and over intersection). The first formula is trivially true if L=∅ or if Jλ=∅ for some λ∈L. If not, let g be an element of ∏λ∈L(⋂ι∈JλXλ,ι). For each λ∈L there exists an index ι∈Jλ such that g(λ)∈Xλ,ι; in other words, the set Hλ of indices ι∈Jλ such that g(λ)∈Xλ,ι is not empty. By Corollary 2 to Proposition 5 there is therefore a functional graph f with domain L such that
f(λ)∈Hλ
for each λ∈L, i.e., g(λ)∈Xλ,f(λ). Hence we have g∈∏λ∈LXλ,f(λ) and consequently g∈⋃f∈I(∏λ∈LXλ,f(λ)). Conversely, if
g∈f∈I⋃(λ∈L∏Xλ,f(λ)),
there is a functional graph f∈I such that for every λ∈L we have
g(λ)∈Xλ,f(λ)
and, a fortiori, g(λ)∈⋃ι∈JλXλ,ι. This completes the proof of the first formula. The proof of the second formula is analogous but simpler, and we leave it to the reader.
Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.