Bourbaki

Exercise 6, § 4

Tag 03LJ, permanent. Cite it as [Bourbaki, Tag 03LJ].

Theory of Sets, III, 231

Bourbaki marks this one as harder than the rest.

(a) Let A be a set and let (Xi)1⩽i⩽m(\mathrm{X}_i)_{1 \leqslant i \leqslant m}, (Yj)m+1⩽j⩽m+n(\mathrm{Y}_j)_{m+1 \leqslant j \leqslant m+n} be two finite families of subsets of A. Let hh be the least integer such that, for each integer r⩽m−hr \leqslant m - h and each subset {i1,…,ir+h}\{i_1, \ldots, i_{r+h}\} of r+hr + h elements of [1,m][1, m], there exists a subset {j1,…,jr}\{j_1, \ldots, j_r\} of rr elements of [m+1,m+n][m + 1, m + n] for which the union of the sets Xiα\mathrm{X}_{i_\alpha} (1⩽α⩽r+h)(1 \leqslant \alpha \leqslant r + h) meets each of the sets Yjβ\mathrm{Y}_{j_\beta} (1⩽β⩽r)(1 \leqslant \beta \leqslant r) (which implies that m⩽n+hm \leqslant n + h). Show that there exists a finite subset B of A with at most n+hn + h elements such that every Xi\mathrm{X}_i (1⩽i⩽m)(1 \leqslant i \leqslant m) and every Yj\mathrm{Y}_j (m+1⩽j⩽m+n)(m + 1 \leqslant j \leqslant m + n) meets B. (Consider the order relation on the interval [1,m+n][1, m + n] whose graph is the union of the diagonal and the set of pairs (i,j)(i, j) such that 1⩽i⩽m1 \leqslant i \leqslant m and m+1⩽j⩽m+nm + 1 \leqslant j \leqslant m + n and Xi∩Yj≠∅\mathrm{X}_i \cap \mathrm{Y}_j \neq \emptyset, and apply Exercise 5 to this ordered set.)

(b) Let E and F be two finite sets and let x→A(x)x \rightarrow \mathrm{A}(x) be a mapping of E into P(F)\mathfrak{P}(\mathrm{F}). Then there exists an injection ff of E into F such that f(x)∈A(x)f(x) \in \mathrm{A}(x) for each x∈Ex \in \mathrm{E} if and only if for each subset H of E we have Card (⋃x∈HA(x))⩾\left( \bigcup_{x \in \mathrm{H}} \mathrm{A}(x) \right) \geqslant Card (H) (the method of proof is analogous to that of (a), with h=0h = 0).

(c) With the hypotheses of (b), let G be a subset of F. Then there exists an injection ff of E into F such that f(x)∈A(x)f(x) \in \mathrm{A}(x) for each x∈Ex \in \mathrm{E} and such that f(E)⊃Gf(E)\supset G if and only if ff satisfies the condition of (b) and for each subset LL of GG the cardinal of the set of all x∈Ex\in E such that A(x)∩L≠∅A(x)\cap L\neq\varnothing is ≥Card⁡(L)\geq\operatorname{Card}(L). (Let (ai)1≤i≤p(a_i)_{1\leq i\leq p} be the sequence of distinct elements of GG, arranged in some order; let (bj)p+1≤j≤p+m(b_j)_{p+1\leq j\leq p+m} be the sequence of distinct elements of FF, arranged in some order; and let

(ck)p+m+1≤k≤p+m+n (c_k)_{p+m+1\leq k\leq p+m+n}

be the sequence of distinct elements of EE, arranged in some order. Consider the order relation on the set [1,p+m+n][1,p+m+n] whose graph is the union of the diagonal and the set of pairs (i,j)(i,j) such that either

1≤i≤pandp+1≤j≤p+mandai=bj, 1\leq i\leq p\quad\text{and}\quad p+1\leq j\leq p+m\quad\text{and}\quad a_i=b_j,

or 1≤i≤p1\leq i\leq p and p+m+1≤j≤p+m+np+m+1\leq j\leq p+m+n and ai∈A(cj)a_i\in A(c_j),

or p+1≤i≤p+mp+1\leq i\leq p+m and p+m+1≤j≤p+m+np+m+1\leq j\leq p+m+n and bi∈A(cj)b_i\in A(c_j);

then apply Exercise 5.)

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