Bourbaki marks this one as harder than the rest.
(a) Let A be a set and let (Xi)1⩽i⩽m, (Yj)m+1⩽j⩽m+n be two finite families of subsets of A. Let h be the least integer such that, for each integer r⩽m−h and each subset {i1,…,ir+h} of r+h elements of [1,m], there exists a subset {j1,…,jr} of r elements of [m+1,m+n] for which the union of the sets Xiα (1⩽α⩽r+h) meets each of the sets Yjβ (1⩽β⩽r) (which implies that m⩽n+h). Show that there exists a finite subset B of A with at most n+h elements such that every Xi (1⩽i⩽m) and every Yj (m+1⩽j⩽m+n) meets B. (Consider the order relation on the interval [1,m+n] whose graph is the union of the diagonal and the set of pairs (i,j) such that 1⩽i⩽m and m+1⩽j⩽m+n and Xi∩Yj=∅, and apply Exercise 5 to this ordered set.)
(b) Let E and F be two finite sets and let x→A(x) be a mapping of E into P(F). Then there exists an injection f of E into F such that f(x)∈A(x) for each x∈E if and only if for each subset H of E we have Card (⋃x∈HA(x))⩾ Card (H) (the method of proof is analogous to that of (a), with h=0).
(c) With the hypotheses of (b), let G be a subset of F. Then there exists an injection f of E into F such that f(x)∈A(x) for each x∈E and such that f(E)⊃G if and only if f satisfies the condition of (b) and for each subset L of G the cardinal of the set of all x∈E such that A(x)∩L=∅ is ≥Card(L). (Let (ai)1≤i≤p be the sequence of distinct elements of G, arranged in some order; let (bj)p+1≤j≤p+m be the sequence of distinct elements of F, arranged in some order; and let
(ck)p+m+1≤k≤p+m+n
be the sequence of distinct elements of E, arranged in some order. Consider the order relation on the set [1,p+m+n] whose graph is the union of the diagonal and the set of pairs (i,j) such that either
1≤i≤pandp+1≤j≤p+mandai=bj,
or 1≤i≤p and p+m+1≤j≤p+m+n and ai∈A(cj),
or p+1≤i≤p+m and p+m+1≤j≤p+m+n and bi∈A(cj);
then apply Exercise 5.)