Bourbaki

Corollary 3

Tag 03N4, permanent. Cite it as [Bourbaki, Tag 03N4].

Theory of Sets, chapter III, § 6. Infinite sets

Let a\mathfrak{a} be an infinite cardinal and let (aι)ι∈I(\mathfrak{a}_\iota)_{\iota \in \mathrm{I}} be a family of cardinals ⩽a\leqslant \mathfrak{a} whose index set I has a cardinal ⩽a\leqslant \mathfrak{a}. Then ∑ι∈Iaι⩽a\sum\limits_{\iota \in \mathrm{I}} \mathfrak{a}_\iota \leqslant \mathfrak{a}; and if aι=a\mathfrak{a}_\iota = \mathfrak{a} for at least one index ι∈I\iota \in \mathrm{I}, then ∑ι∈Iaι=a\sum\limits_{\iota \in \mathrm{I}} \mathfrak{a}_\iota = \mathfrak{a}.

Let b\mathfrak{b} be the cardinal of I; then we have ∑ι∈Iaι⩽ab⩽a2=a\sum\limits_{\iota \in \mathrm{I}} \mathfrak{a}_\iota \leqslant \mathfrak{a}\mathfrak{b} \leqslant \mathfrak{a}^2 = \mathfrak{a} (§ 3, no. 6, Proposition 14), and ∑ι∈Iaι⩾aϰ\sum\limits_{\iota \in \mathrm{I}} \mathfrak{a}_\iota \geqslant \mathfrak{a}_\varkappa for all ϰ∈I\varkappa \in \mathrm{I}.

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

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Transcribed from the printed edition, 2004, Springer. Not translated.