Let a be an infinite cardinal and let (aι)ι∈I be a family of cardinals ⩽a whose index set I has a cardinal ⩽a. Then ι∈I∑aι⩽a; and if aι=a for at least one index ι∈I, then ι∈I∑aι=a.
Let b be the cardinal of I; then we have ι∈I∑aι⩽ab⩽a2=a (§ 3, no. 6, Proposition 14), and ι∈I∑aι⩾aϰ for all ϰ∈I.
Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.