Let(aι)ι∈Iand(bι)ι∈Ibe two families of cardinals, both indexed by the same set I, and such thataι⩾bιfor allι∈I. Then
ι∈I∑aι⩾ι∈I∑bι,Pι∈Iaι⩾Pι∈Ibι.
The second inequality follows from the inclusion relations between products of sets (Chapter II, § 5, no. 4, Proposition 6, Corollary 3). As to the first inequality, if a set E is the union of a family (Aι)ι∈I of mutually disjoint subsets and if Bι⊂Aι for all ι∈I, then the Bι are also mutually disjoint and ⋃ιBι⊂⋃ιAι (Chapter II, § 4, no. 2).
Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.