Bourbaki

Definition 5

Tag 03PY, permanent. Cite it as [Bourbaki, Tag 03PY].

Theory of Sets, chapter II, § 4. Union and intersection of a family of sets

A family of sets (Xι)ι∈I(\mathrm{X}_\iota)_{\iota \in \mathrm{I}} is said to be a covering of a set E (or to cover E) if E⊂⋃ι∈IXι\mathrm{E} \subset \bigcup\limits_{\iota \in \mathrm{I}} \mathrm{X}_\iota. If (Xι)ι∈I(\mathrm{X}_\iota)_{\iota \in \mathrm{I}} and (Yϰ)ϰ∈K(\mathrm{Y}_\varkappa)_{\varkappa \in \mathrm{K}} are coverings of E, the second of these coverings is said to be finer than the first (or to be a refinement of the first, or to refine the first) if, for each ϰ∈K\varkappa \in \mathrm{K}, there exists ι∈I\iota \in \mathrm{I} such that

Yϰ⊂Xι.\mathrm{Y}_\varkappa \subset \mathrm{X}_\iota.

A set of sets R\mathfrak{R} is a covering of E if the family of sets defined by the identity mapping of R\mathfrak{R} is a covering of E, in other words, if E⊂⋃X∈RX\mathrm{E} \subset \bigcup\limits_{\mathrm{X} \in \mathfrak{R}} \mathrm{X}.

If R\mathfrak{R}, R′\mathfrak{R}', R′′\mathfrak{R}'' are three coverings of E such that R′\mathfrak{R}' refines R\mathfrak{R} and R′′\mathfrak{R}'' refines R′\mathfrak{R}', it is clear that R′′\mathfrak{R}'' refines R\mathfrak{R}.

Let (Xι)ι∈I(\mathrm{X}_\iota)_{\iota \in \mathrm{I}} be a covering of E. If J is a subset of I such that (Xι)ι∈J(\mathrm{X}_\iota)_{\iota \in \mathrm{J}} is still a covering of E, then this covering clearly refines (Xι)ι∈I(\mathrm{X}_\iota)_{\iota \in \mathrm{I}}.

¶ Let (Xι)ι∈I(\mathrm{X}_\iota)_{\iota \in \mathrm{I}} and (Yϰ)ϰ∈K(\mathrm{Y}_\varkappa)_{\varkappa \in \mathrm{K}} be coverings of a set E. Then the family of sets (Xι∩Yϰ)(ι,ϰ)∈I×K(\mathrm{X}_\iota \cap \mathrm{Y}_\varkappa)_{(\iota, \varkappa) \in \mathrm{I} \times \mathrm{K}} is a covering of E. For if x∈Ex \in \mathrm{E}, there exist indices ι∈I\iota \in \mathrm{I} and ϰ∈K\varkappa \in \mathrm{K} such that x∈Xιx \in \mathrm{X}_\iota and x∈Yϰx \in \mathrm{Y}_\varkappa, so that x∈Xι∩Yϰx \in \mathrm{X}_\iota \cap \mathrm{Y}_\varkappa Moreover, it is clear that the covering (Xι∩Yϰ)(ι,ϰ)∈I×K(\mathrm{X}_\iota \cap \mathrm{Y}_\varkappa)_{(\iota, \varkappa) \in \mathrm{I} \times \mathrm{K}} refines each o the coverings (Xι)ι∈I(X_\iota)_{\iota \in I}, (Yϰ)ϰ∈K(Y_\varkappa)_{\varkappa \in K}. Conversely, let (Zλ)λ∈L(Z_\lambda)_{\lambda \in L} be a covering of E which refines each of the coverings (Xι)ι∈I(X_\iota)_{\iota \in I}, (Yϰ)ϰ∈K(Y_\varkappa)_{\varkappa \in K}; if λ∈L\lambda \in L, then there exist indices ι∈I\iota \in I and ϰ∈K\varkappa \in K such that Zλ⊂XιZ_\lambda \subset X_\iota and Zλ⊂YϰZ_\lambda \subset Y_\varkappa, so that Zλ⊂Xι∩YϰZ_\lambda \subset X_\iota \cap Y_\varkappa; hence the covering (Zλ)λ∈L(Z_\lambda)_{\lambda \in L} is a refinement of

(Xι∩Yϰ)(ι,ϰ)∈I×K.(X_\iota \cap Y_\varkappa)_{(\iota, \varkappa) \in I \times K}.

¶ Let (Xι)ι∈I(X_\iota)_{\iota \in I} be a covering of a set A, and let ff be a mapping of A onto a set B. The family (f⟨Xι⟩)ι∈I(f\langle X_\iota \rangle)_{\iota \in I} is then a covering of B (Proposition 3), called the image under ff of the covering (Xι)ι∈I(X_\iota)_{\iota \in I}. If gg is a mapping of a set C into the set A, the family (g−1⟨Xι⟩)ι∈I(\overset{-1}{g}\langle X_\iota \rangle)_{\iota \in I} is a covering of C, called the inverse image under gg of the covering (Xι)ι∈I(X_\iota)_{\iota \in I}. ¶ Let E and F be sets, let (Xι)ι∈I(X_\iota)_{\iota \in I} be a covering of E, and let (Yϰ)ϰ∈K(Y_\varkappa)_{\varkappa \in K} be a covering of F. The family (Xι×Yϰ)(ι,ϰ)∈I×K(X_\iota \times Y_\varkappa)_{(\iota, \varkappa) \in I \times K} is then a covering of E×FE \times F, called the product of the coverings (Xι)ι∈I(X_\iota)_{\iota \in I} of E and (Yϰ)ϰ∈K(Y_\varkappa)_{\varkappa \in K} of F.

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

Cited by

  • top-i-s9-def-6 not in this corpus

Cites

Transcribed from the printed edition, 2004, Springer. Not translated.