A family of sets (Xι)ι∈I is said to be a covering of a set E (or to cover E) if E⊂ι∈I⋃Xι. If (Xι)ι∈I and (Yϰ)ϰ∈K are coverings of E, the second of these coverings is said to be finer than the first (or to be a refinement of the first, or to refine the first) if, for each ϰ∈K, there exists ι∈I such that
Yϰ⊂Xι.
A set of sets R is a covering of E if the family of sets defined by the identity mapping of R is a covering of E, in other words, if E⊂X∈R⋃X.
If R, R′, R′′ are three coverings of E such that R′ refines R and R′′ refines R′, it is clear that R′′ refines R.
Let (Xι)ι∈I be a covering of E. If J is a subset of I such that (Xι)ι∈J is still a covering of E, then this covering clearly refines (Xι)ι∈I.
¶ Let (Xι)ι∈I and (Yϰ)ϰ∈K be coverings of a set E. Then the family of sets (Xι∩Yϰ)(ι,ϰ)∈I×K is a covering of E. For if x∈E, there exist indices ι∈I and ϰ∈K such that x∈Xι and x∈Yϰ, so that x∈Xι∩Yϰ Moreover, it is clear that the covering (Xι∩Yϰ)(ι,ϰ)∈I×K refines each o the coverings (Xι)ι∈I, (Yϰ)ϰ∈K. Conversely, let (Zλ)λ∈L be a covering of E which refines each of the coverings (Xι)ι∈I, (Yϰ)ϰ∈K; if λ∈L, then there exist indices ι∈I and ϰ∈K such that Zλ⊂Xι and Zλ⊂Yϰ, so that Zλ⊂Xι∩Yϰ; hence the covering (Zλ)λ∈L is a refinement of
(Xι∩Yϰ)(ι,ϰ)∈I×K.
¶ Let (Xι)ι∈I be a covering of a set A, and let f be a mapping of A onto a set B. The family (f⟨Xι⟩)ι∈I is then a covering of B (Proposition 3), called the image under f of the covering (Xι)ι∈I. If g is a mapping of a set C into the set A, the family (g−1⟨Xι⟩)ι∈I is a covering of C, called the inverse image under g of the covering (Xι)ι∈I. ¶ Let E and F be sets, let (Xι)ι∈I be a covering of E, and let (Yϰ)ϰ∈K be a covering of F. The family (Xι×Yϰ)(ι,ϰ)∈I×K is then a covering of E×F, called the product of the coverings (Xι)ι∈I of E and (Yϰ)ϰ∈K of F.
Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.