Bourbaki

Remark 2

Tag 03SB, permanent. Cite it as [Bourbaki, Tag 03SB].

Theory of Sets, chapter II, § 5. Product of a family of sets

Let α\alpha, β\beta, γ\gamma be three objects, no two of which are equal (three such objects exist; for example, ∅\emptyset, {∅}\{\emptyset\}, {{∅}}\{\{\emptyset\}\}), and let A, B, C be sets. Consider the functional graph {(α,A),(β,B),(γ,C)}\{(\alpha, A), (\beta, B), (\gamma, C)\}, i.e., the family of sets (Xι)ι∈{α,β,γ}(X_\iota)_{\iota \in \{\alpha, \beta, \gamma\}} such that Xα=AX_\alpha = A, Xβ=BX_\beta = B, Xγ=CX_\gamma = C. To the partition of {α,β,γ}\{\alpha, \beta, \gamma\} formed by the two sets {α,β}\{\alpha, \beta\} and {γ}\{\gamma\} there corresponds a canonical bijection of ∏ι∈{α,β,γ}Xι\prod_{\iota \in \{\alpha, \beta, \gamma\}} X_\iota onto the product

(∏ι∈{α,β}Xι)×Xγ{γ},\left( \prod_{\iota \in \{\alpha, \beta\}} X_\iota \right) \times X_\gamma^{\{\gamma\}},

and hence a bijection (again called canonical) of ∏ι∈{α,β,γ}Xι\prod_{\iota \in \{\alpha, \beta, \gamma\}} X_\iota onto A×B×CA \times B \times C (§ 2, no. 2) which transforms each graph f∈∏ι∈{α,β,γ}Xιf \in \prod_{\iota \in \{\alpha, \beta, \gamma\}} X_\iota into the element (f(α),f(β),f(γ))(f(\alpha), f(\beta), f(\gamma)) of A×B×CA \times B \times C. By Proposition 4 we may therefore put any two of the six sets A×B×CA \times B \times C, B×C×AB \times C \times A, C×A×BC \times A \times B, B×A×CB \times A \times C, A×C×BA \times C \times B, C×B×AC \times B \times A in one-to-one correspondence.

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

Cited by

Nothing.

Cites

Transcribed from the printed edition, 2004, Springer. Not translated.