Exercise 19, § 1
Tag 03UF, permanent. Cite it as [Bourbaki, Tag 03UF].
Theory of Sets, III, 219
An ordered set E is said to be without gaps if it contains two distinct comparable elements and if, for each pair of elements , such that , the open interval is not empty. Show that an ordinal sum (Exercise 3) is without gaps if and only if the following conditions are satisfied :
(I) Either I contains two distinct comparable elements, or else there exists such that contains two distinct comparable elements.
(II) Each which contains at least two distinct comparable elements is without gaps.
(III) If , are two elements of I such that , and if the interval in I is empty, then either has no maximal element or else has no minimal element.
In particular, every ordinal sum of sets without gaps is itself without gaps provided that no has a maximal element (or provided that no has a minimal element). If I is without gaps, and if each is either without gaps or contains no two distinct comparable elements, then is without gaps.
Solution
No solution has been written yet.