Bourbaki

Exercise 22, § 1

Tag 03UI, permanent. Cite it as [Bourbaki, Tag 03UI].

Theory of Sets, III, 220

Bourbaki marks this one as harder than the rest.

(a) Let E be an ordered set. A subset U of E is said to be open if, for each x∈Ux \in U, U contains the interval [x,→[[x, \rightarrow[. An open set U is said to be regular if there exists no open set V⊃UV \supset U, distinct from U, such that U is cofinal in V. Show that every open set U is cofinal in exactly one regular open set U~\tilde{U} [^1]. The mapping U→U~U \rightarrow \tilde{U} is increasing. If U, V are two open sets such that U∩V=∅U \cap V = \emptyset, then also U~∩V~=∅\tilde{U} \cap \tilde{V} = \emptyset.

(b) Show that the set R(E)R(E) of regular open subsets of E, ordered by inclusion, is a complete Boolean lattice (Exercise 17). For R(E)R(E) to consist of two elements it is necessary and sufficient that E should be non-empty and right directed.

(c) If F is a cofinal subset of E, show that the mapping U→U∩FU \rightarrow U \cap F is an isomorphism of R(E)R(E) onto R(F)R(F).

(d) If E1E_1, E2E_2 are two ordered sets, then every open set in E1×E2E_1 \times E_2 is of the form U1×U2U_1 \times U_2, where UiU_i is open in EiE_i (i=1i=1, 2). The set R(E1×E2)R(E_1 \times E_2) is isomorphic to R(E1)×R(E2)R(E_1) \times R(E_2).

[^1]: This terminology may be justified by noting that there exists a unique topology on E for which the open sets (resp. regular open sets) are those defined in Exercise 22 (a) (cf. General Topology, Chapter I, § 1, Exercise 2 and § 8, Exercise 20).

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