Let Σ be the species of topological structures (no. 4, Example 3), let A be the (principal) base set, and let V be the generic structure of Σ. Consider the relation
x∈A and X⊂A and (∀U)((U∈V and x∈U)⇒(X∩U=∅)).
This relation has a graph P⊂P(A)×A with respect to the pair (X,x); P∣A,V is a term called “the set of all pairs (X,x) such that x lies in the closure of X with respect to the topology V”. We can then prove (cf. General Topology, Chapter I, § 1) that the following relations are theorems in TΣ:
P(∅)=∅,
(∀Y)((Y⊂A)⇒(∀Y⊂P(Y))),
(∀Y)((Y⊂A)⇒(P(P(Y))=P(Y))),
(∀Y)(∀Z)((Y⊂A and Z⊂A)⇒(P(Y∪Z)=P(Y)∪P(Z))).
Consider the species of structures Θ, having a single (principal) base set A, whose generic structure consists of a single letter W, which has as typical characterization W∈P(P(A)×A) and as axiom
W(∅)=∅ and (∀Y)((Y⊂A)⇒(Y⊂W(Y)))
and
(∀Y)((Y⊂A)⇒(W(W(Y))=W(Y)))
and
(∀Y)(∀Z)((Y⊂A and Z⊂A)⇒(W(Y∪Z)=W(Y)∪W(Z))).
Consider also the relation
U⊂A and (∀x)((x∈U)⇒x∈/W(A−U)).
The set of all U∈P(A) which satisfy this relation is a subset Q∣A,W of P(A). We can then prove (General Topology, Chapter I, § 1, Exercise 10) that the following relations are theorems in TΘ:
(∀M)((M⊂Q)⇒((X∈M⋃X)∈Q)),
(∀X)(∀Y)((X∈Q and Y∈Q)⇒((X∩Y)∈Q)).
Thus the terms P{A,V} and Q{A,W} satisfy conditions (1) and (2) above, and it is easily seen that they also satisfy condition (3). The species of structures Σ and Θ are therefore equivalent, and we therefore consider every structure of species Θ as a topology, namely that which corresponds to it under the procedure of deduction Q{A,W}. \*
Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.
Nothing.