Bourbaki

Lemma 4

Tag 04AK, permanent. Cite it as [Bourbaki, Tag 04AK].

Commutative Algebra, chapter II, § 4. Spectra of rings and supports of modules

Let A,BA, B be two local rings, p:A→Bp : A \to B a local homomorphism and EE a finitely generated AA-module. If E≠0E \neq 0, then E(B)≠0E_{(B)} \neq 0.

Let mm be the maximal ideal of AA and k=A/mk = A/m the residue field; the hypothesis implies that B⊗Ak=B/mB≠0B \otimes_A k = B/mB \neq 0; since the tensor product is associative, (E⊗AB)⊗Ak(E \otimes_A B) \otimes_A k is isomorphic to E⊗A(B⊗Ak)E \otimes_A (B \otimes_A k), hence also to E⊗A(k⊗k(B⊗Ak))E \otimes_A (k \otimes_k (B \otimes_A k)) and finally to (E⊗Ak)⊗k(B⊗Ak)(E \otimes_A k) \otimes_k (B \otimes_A k); by § 3, no. 2, Proposition 4, E⊗Ak≠0E \otimes_A k \neq 0, hence (E⊗AB)⊗Ak≠0(E \otimes_A B) \otimes_A k \neq 0 (Algebra, Chapter II, § 3, no. 7) and a fortiori E⊗AB≠0E \otimes_A B \neq 0.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Transcribed from the printed volume. Not translated.