Bourbaki

Example 1

Tag 04MV, permanent. Cite it as [Bourbaki, Tag 04MV].

Commutative Algebra, chapter V, § 1. Notion of an integral element

Let KK be a (commutative) field and RR a KK-algebra; to say that an element x∈Rx \in R is integral over KK is equivalent to saying that xx is a root of a non-constant polynomial in the ring K[X]K[X]; generalizing the terminology introduced when RR is an extension of KK (Algebra, Chapter V, § 3, no. 3), the elements x∈Rx \in R which are integral over KK are also called the algebraic elements of RR over KK.

(2) The elements of Q(i)\mathbf{Q}(i) which are integral over Z\mathbf{Z} are the elements of the form a+iba + ib where a∈Za \in \mathbf{Z} and b∈Zb \in \mathbf{Z} ("*Gaussian integers*"'); the elements of Q(5)\mathbf{Q}(\sqrt{5}) which are integral over Z\mathbf{Z} are the elements of the form (a+b5)/2(a + b\sqrt{5})/2 where aa and bb belong to Z\mathbf{Z} and are both even or both odd (for these two examples see Exercise 1).

(3) The complex numbers integral over Z\mathbf{Z} are also called algebraic integers.

Remarks (1) Let A′A' be the subring of RR (contained in the centre of RR) the image of AA under the ring homomorphism A→RA \to R which defines the AA-algebra structure on RR. Clearly it is equivalent to say that an element of RR is integral over AA or that it is integral over A′A'.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Transcribed from the printed volume. Not translated.