Proposition 1
Tag 051P, permanent. Cite it as [Bourbaki, Tag 051P].
Commutative Algebra, chapter VII, § 3. Factorial domains
Let A be a Krull domain. If every divisorial ideal of A is invertible, then, for every maximal ideal m of A, is factorial. The converse is true if it is also assumed that every divisorial ideal of A is finitely generated (in particular if A is Noetherian).
Suppose that every divisorial ideal of is invertible; as is a Krull domain (, no. 4, Proposition 6), every divisorial ideal of is the intersection of two principal fractional ideals (, no. 5, Corollary 2 to Proposition 9); hence , where is a divisorial ideal of (Chapter II, , no. 4); as is invertible by hypothesis, we deduce from Chapter II, , no. 6, Theorem 4 that is principal and hence is a factorial domain (no. 1, Definition 1). Conversely, if all the are factorial and is a finitely generated divisorial ideal of , is a divisorial ideal of , as follows from , no. 5, Corollary 2 to Proposition 9 and Chapter II, , no. 4; by hypothesis is principal and hence it follows from Chapter 11, , no. 6, Theorem 4 that is invertible.
Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.