Bourbaki

Definition 5

Tag 058X, permanent. Cite it as [Bourbaki, Tag 058X].

Algebra, chapter I, § 4. Groups and groups with operators

Let G be a group with operators. A stable subgroup H of G is called a normal (or invariant) stable subgroup of G if xHx−1=HxHx^{-1} = H for all x∈Gx \in G.

If Ω=∅\Omega = \varnothing, a normal stable subgroup of G is called a normal (or invariant) subgroup of G. In a commutative group every subgroup is normal.

To verify that a stable subgroup H is normal, it suffices to show that xHx−1⊂HxHx^{-1} \subset H for all x∈Gx \in G; for if so then x−1Hx⊂Hx^{-1}Hx \subset H for all x∈Gx \in G, that is H⊂xHx−1H \subset xHx^{-1}, and hence H=xHx−1H = xHx^{-1}.

Let H be a normal stable subgroup of G and R the equivalence relation y∈xHy \in xH defined by H; on the quotient set G/RG/R, the internal law, the quotient by R of the law of the group G, is associative; the class of e is the identity element of this quotient law; the classes of two inverse elements in G are inverses under the quotient law and the action of Ω\Omega, the quotient by R of the action of Ω\Omega on G, is distributive with respect to the internal law on G/RG/R (§\S 3, no. 5). Hence, summarizing the results obtained:

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Transcribed from the printed edition, 1998, Springer. Not translated.