Bourbaki

Proposition 9

Tag 059H, permanent. Cite it as [Bourbaki, Tag 059H].

Algebra, chapter I, § 4. Groups and groups with operators

For a decomposition series of G to be a Jordan-Hölder series it is necessary and sufficient that all the quotients of the series be simple.

A decomposition series is strictly decreasing if and only if none of its successive quotients is reduced to the identity element. If a strictly decreasing composition series Σ\Sigma is not a Jordan-Hölder series, there exists a strictly decreasing composition series Σ′\Sigma' which is finer than Σ\Sigma and distinct from Σ\Sigma. There are therefore two consecutive terms Gi,Gi+1G_i, G_{i+1} of Σ\Sigma which are not consecutive in Σ′\Sigma'; let HH be the first term which follows GiG_i in Σ′\Sigma'; HH is a normal stable subgroup of GiG_i, containing Gi+1G_{i+1} and distinct from the latter; hence H/Gi+1H/G_{i+1} is a normal stable subgroup of Gi/Gi+1G_i/G_{i+1}, distinct from the latter and from the identity element; therefore Gi/Gi+1G_i/G_{i+1} is not simple. Conversely, if Σ\Sigma is a strictly decreasing composition series one of whose quotients Gi/Gi+1G_i/G_{i+1} is not simple, this quotient contains a normal stable subgroup other than itself and {e}\{e\}, whose inverse image in GiG_i is a normal stable subgroup HH of GiG_i, distinct from GiG_i and Gi+1G_{i+1} (Theorem 4); it suffices to insert HH between GiG_i and Gi+1G_{i+1} to obtain a strictly decreasing composition series distinct from Σ\Sigma and finer than Σ\Sigma.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Cites

Transcribed from the printed edition, 1998, Springer. Not translated.