(a) Let E be a (B, A)-bimodule, F a left A-module and G a left B-module. For every mapping g∈HomB(E⊗AF,G), let g′ be the mapping of F into HomB(E,G) defined by (g′(y))(x)=g(x⊗y) for x∈E,y∈F. The mapping g↦g′ is an isomorphism
(5)
β:HomB(E⊗AF,G)→HomA(F,HomB(E,G)).
(b) Let E be a right A-module, F an (A, C)-bimodule and G a right C-module. For every mapping h∈HomC(E⊗AF,G), let h′ be the mapping of E into HomC(F,G) defined by (h′(x))(y)=h(x⊗y) for x∈E,y∈F. The mapping h↦h′ is an isomorphism
(6)
γ:HomC(E⊗AF,G)→HomA(E,HomC(F,G)).
In particular B and C may be taken to be a subring Γ of the centre of the ring A; then for every Γ-module G, the three Γ-modules
HomΓ(E⊗AF,G),HomA(E,HomΓ(F,G)),HomA(F,HomΓ(E,G))
are canonically isomorphic to the Γ-module of Γ-*bilinear* mappings of E×F into G which satisfy (1). More particularly:
Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.
Nothing.