Bourbaki

Lemma 1

Tag 05PS, permanent. Cite it as [Bourbaki, Tag 05PS].

Algebra, chapter II, § 4. Relations between tensor products and homomorphism modules

For every homomorphism u:F→F′u : F \to F', the diagram

T(F)→νFT′(F)↓T(u)↓T′(u)T(F′)→νF′T′(F′) \begin{array}{ccc} T(F) & \xrightarrow{\nu_F} & T'(F) \\ \downarrow T(u) & & \downarrow T'(u) \\ T(F') & \xrightarrow{\nu_{F'}} & T'(F') \end{array}

is commutative.

The verification is immediate.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

Cited by

Cites

Nothing.

Transcribed from the printed edition, 1998, Springer. Not translated.