Let C be a commutative ring, E,F two finitely generated projective C-modules* and u:E→F and v:F→E two linear mappings; then*
Tr(v∘u)=Tr(u∘v).
The two mappings (u,v)↦Tr(u∘v),(u,v)↦Tr(v∘u) of
HomC(E,F)×HomC(F,E)
into C are C*-bilinear*; it therefore suffices to verify (20) when u is of the form x↦⟨x,a∗⟩b and v of the form y↦⟨y,b∗⟩a, with a∈E,a∗∈E∗,b∈F,b∗∈F∗. But then v∘u is the mapping x↦⟨x,a∗⟩⟨b,b∗⟩a and u∘v the mapping y↦⟨y,b∗⟩⟨a,a∗⟩b. Formula (17) shows that the values of the two sides of (20) are equal to ⟨a,a∗⟩⟨b,b∗⟩.
Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.
Nothing.