Bourbaki

Proposition 4

Tag 05WT, permanent. Cite it as [Bourbaki, Tag 05WT].

Algebra, chapter II, § 10. Matrices

Let E be a right A-module with finite basis (ei)1≤i≤n(e_i)_{1 \leq i \leq n} of n elements. For a family of n elements ei′=∑j=1nejaji(1≤i≤n)e'_i = \sum_{j=1}^n e_j a_{ji} (1 \leq i \leq n) to be a basis of E, it is necessary and sufficient that the square matrix P=(aji)P = (a_{ji}) of order n be invertible.

PP is just the matrix, with respect to the basis (ei)(e_i) of the endomorphism uu of E defined by u(ei)=ei′(1≤i≤n)u(e_i) = e'_i (1 \leq i \leq n). Now, for uu to be an automorphism of E, it is necessary and sufficient that (u(ei))(u(e_i)) be a basis of E (§ 1, no. 11, Corollary 3 to Proposition 17); whence the proposition.

The invertible matrix PP is called the matrix of passage from the basis (ei)(e_i) to the basis (ei′)(e'_i). It can also be interpreted as the matrix of the identity mapping lEl_E with respect to the bases (ei′)(e'_i) and (ei)(e_i) (in that order); then clearly the matrix of passage from the basis (ei′)(e'_i) to the basis (ei)(e_i) is the inverse P−1P^{-1} of PP.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Transcribed from the printed edition, 1998, Springer. Not translated.