Bourbaki

Example

Tag 05YS, permanent. Cite it as [Bourbaki, Tag 05YS].

Algebra, chapter III, § 1. Algebras

(1) Every commutative ring AA can be considered as an (associative and commutative) AA-algebra. (2) Let EE be a pseudo-ring (I, § 8, no. 1). Multiplication on EE and the unique Z\mathbf{Z}-module structure on EE define on EE an associative Z\mathbf{Z}-algebra structure. (3) Let FF be a set and AA a commutative ring. The set AFA^F of all mappings of FF into AA, with the product ring structure (I, § 8, no. 10) and the product

A-module structure (II, § 1, no. 5) is an associative and commutative A-algebra.

(4) Let E be an A-algebra; the internal laws (x,y)↦xy+yx(x, y) \mapsto xy + yx and (x,y)↦xy−yx(x, y) \mapsto xy - yx define (with the A-module structure on E) two A-algebra structures on E, which are not in general associative; the first law

(x,y)↦xy+yx(x, y) \mapsto xy + yx

is always commutative.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

Cited by

Nothing.

Cites

Transcribed from the printed edition, 1998, Springer. Not translated.