Bourbaki

Definition 2

Tag 05YT, permanent. Cite it as [Bourbaki, Tag 05YT].

Algebra, chapter III, § 1. Algebras

Given two algebras E, E' over a commutative ring A, a homomorphism of E into E' is a mapping f:E→E′f : E \to E' such that (1) f is an A*-module homomorphism*; (2) f(xy)=f(x)f(y)f(xy) = f(x)f(y) for all x∈Ex \in E and y∈Ey \in E.

Clearly the composition of two A-algebra homomorphisms is an A-algebra homomorphism. Every bijective algebra homomorphism is an isomorphism. Therefore A-algebra homomorphisms may be taken as morphisms of the species of A-algebra structure (Set Theory, IV, 2, no. 1). We shall always suppose in what follows that this choice of morphisms has been made. If E, E' are two A-algebras, let Hom⁡A-alg(E,E′)\operatorname{Hom}_{A\text{-alg}}(E, E') denote the set of A-algebra homomorphisms of E into E'.

Let E, E' be two algebras each with a unit element. A homomorphism of E into E' mapping the unit element of E to the unit element of E' is called a unital homomorphism (or unital algebra morphism).

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Transcribed from the printed edition, 1998, Springer. Not translated.