Bourbaki

Definition 2

Tag 05Z7, permanent. Cite it as [Bourbaki, Tag 05Z7].

Algebra, chapter III, § 2. Examples of algebras

Let I be a set; let M(I) (resp. Mo(I), resp. N(I)\mathbf{N}^{(I)}) denote the free magma (resp. free monoid, resp. free commutative monoid) derived from I. The algebra of M(I) (resp. Mo(I), resp. N(I)\mathbf{N}^{(I)}) over A is called the free algebra (resp. free associative algebra, resp. free commutative associative algebra (or, by an abuse of language, free commutative algebra)) of the set I over the ring A.

We shall denote the free algebra (resp. free associative algebra, resp. free commutative algebra) of I over A by Lib_A(I) (resp. Libas_A(I), resp. Libasc_A(I)). By composing the canonical mapping of I into M(I) (resp. Mo(I), resp. N(I)\mathbf{N}^{(I)}) with the canonical mapping of M(I) (resp. Mo(I), resp. N(I)\mathbf{N}^{(I)}) into Lib_A(I) (resp. Libas_A(I), resp. Libasc_A(I)), a canonical mapping is obtained of I into Lib_A(I) (resp. Libas_A(I), resp. Libasc_A(I)), which is injective if A≠{0}A \neq \{0\}. We shall denote the image of an element i∈Ii \in I under this canonical mapping by XiX_i and we shall say that XiX_i is the indeterminate of index i of Lib_A(I) (resp. Libas_A(I), resp. Libasc_A(I)).

As Mo(I) and N(I)\mathbf{N}^{(I)} each have an identity element, Libas_A(I) and Libasc_A(I) are unital associative algebras and further Libasc_A(I) is commutative. If e is the unit element of Libas_A(I) (resp. Libasc_A(I)), the mapping α↦αe\alpha \mapsto \alpha e is an isomorphism of A onto a subring of the centre of Libas_A(I) (resp. Libasc_A(I)), which is identified with A (no. 1).

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Cites

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Transcribed from the printed edition, 1998, Springer. Not translated.