Bourbaki

Definition 3

Tag 060J, permanent. Cite it as [Bourbaki, Tag 060J].

Algebra, chapter III, § 4. Tensor products of algebras

Let E and F be two (unital) A-algebras and M a set with an E-module structure and an F-module structure. M is called a (left) bimodule over the algebras E and F if:

(1) M is a bimodule over the underlying rings of E and F (II, § 1, no. 14); (2) the two A-module structures underlying the E-module and F-module structures on M are identical.

The latter condition says that if e and e′e' are the unit elements of E and F respectively, then

(αe)x=(αe′)xfor α∈A,x∈M; (\alpha e)x = (\alpha e')x \quad \text{for } \alpha \in A, x \in M;

then αx\alpha x is used to denote the common value of the two sides.

It can also be said that being given on M a bimodule structure over E and F is equivalent to being given an A-module structure on M and also two A-algebra homomorphisms s↦hs′s \mapsto h'_s of E into EndA(M)\mathrm{End}_A(M) and t↦ht′′t \mapsto h''_t of F into EndA(M)\mathrm{End}_A(M) such that hs′ht′′=ht′′hs′h'_s h''_t = h''_t h'_s for all s∈Es \in E and t∈Ft \in F. Consequently (no. 2, Proposition 5) an A-algebra homomorphism u↦huu \mapsto h_u of E⊗AFE \otimes_A F into EndA(M)\mathrm{End}_A(M) is canonically derived such that hs⊗t=hs′ht′′=ht′′hs′h_{s \otimes t} = h'_s h''_t = h''_t h'_s for s∈Es \in E and t∈Ft \in F. In other words, an (E⊗AF)(E \otimes_A F)-module structure is thus defined on M, which is said to be associated with the given bimodule structure over E and F and under which

(s⊗t).x=s(tx)=t(sx)for s∈E,t∈F and x∈M. (s \otimes t).x = s(tx) = t(sx) \quad \text{for } s \in E, t \in F \text{ and } x \in M.

The given E-module and F-module structures on M can be derived from this (E⊗AF)(E \otimes_A F)-module structure by restrictions of the ring of scalars, corresponding to the two canonical homomorphisms E→E⊗AFE \to E \otimes_A F and F→E⊗AFF \to E \otimes_A F.

Conversely, if an (E⊗AF)(E \otimes_A F)-module structure is given on M, by means of the canonical homomorphisms E→E⊗AFE \to E \otimes_A F and F→E⊗AFF \to E \otimes_A F an E-module structure and an F-module structure on M and it is immediate that M is a bimodule over the algebras E and F with these two structures and that the given (E⊗AF)(E \otimes_A F)-module structure is associated with this bimodule structure.

Thus a one-to-one correspondence has been established between (E⊗AF)(E \otimes_A F)-module and bimodules over the algebras E and F. Clearly every sub-bimodule of M is a submodule for the associated (E⊗AF)(E \otimes_A F)-module structure and conversely. There are analogous results for quotients, products, direct sums and inverse and direct limits. Finally, if M′M' is another bimodule over the algebras E and F and f:M→M′f : M \to M' is a bimodule homomorphism, ff is also an (E⊗AF)(E \otimes_A F)-module homomorphism and conversely.

There are obviously corresponding statements for right bimodule structures, or when for example there is a left E-module structure and a right F-module structure; in this case we speak of an (E,F)(E, F)-bimodule and being given such a structure amounts to being given a left bimodule structure over E and FoF^o.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Cites

Transcribed from the printed edition, 1998, Springer. Not translated.