Example
Tag 060K, permanent. Cite it as [Bourbaki, Tag 060K].
Algebra, chapter III, § 4. Tensor products of algebras
(1) Let B be an A-algebra; the ring B has canonically a (B, B)-bimodule structure (II, § 1, no. 14, Example 1) and, if e is the unit element of B, then for all and all ; B can therefore be considered as a left bimodule over the algebras B and (opposite to B); there is therefore associated with the (B, B)-bimodule structure on B a (B )-module structure such that, for and in B,
the right-hand side being the product in the ring B.
(2) Let E and F be two A-algebras, their respective unit elements, M an E-module and N an F-module; these module structures define on M a bimodule structure over the rings A and E and on N a bimodule structure over the rings A and F; from these is therefore derived a bimodule structure over the rings E and F on the tensor product , defined by
for (II, § 3, no. 4); it is also seen that conditions (8) hold and hence the above bimodule structure is associated with an -module structure on , such that
for .
In particular, taking has canonically an -module structure; on the other hand, is canonically identified with , where is considered as having its right F-module structure defined by the canonical homomorphism ; for in E, , is thus identified with and with . The -module is thus identified with the -module derived from N by extending the scalars to by means of the homomorphism (II, § 5, no. 1). The canonical mapping of N into is identified with the canonical mapping of N into ; this is known to be an F-homomorphism.
With the same notation, let P be a right (E \otimes_A F)-module; then there is a canonical Z-module isomorphism
(11)
where on the right-hand side P is considered as a right F-module by means of the canonical homomorphism . For P is canonically identified with and with and hence with , which establishes the stated isomorphism (II, § 3, no. 8, Proposition 8 and II, § 3, no. 4, proposition 4).
All the above extends to multimodules (II, § 1, no. 14).
Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.
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