Bourbaki

Lemma 1

Tag 064E, permanent. Cite it as [Bourbaki, Tag 064E].

Algebra, chapter III, § 8. Determinants

*Let A be a commutative ring and M a free A-module with a basis (ej)j∈J(e_j)_{j \in J}, where the indexing set J is totally ordered. For every integer p≤Card(J)p \leq \mathrm{Card}(J), every alternating p-linear function f:Mp→Nf : M^p \to N (where N is an A-module) and every family of p elements xi=∑j∈Jξjiejx_i = \sum_{j \in J} \xi_{ji} e_j of M (1≤i≤p)(1 \leq i \leq p),

f(x1,x2,…,xp)=∑j1<j2<⋯<jp(∑σ∈Spεσ⋅ξjσ(1),1ξjσ(2),2⋯ξjσ(p),p)f(ej1,…,ejp) f(x_1, x_2, \ldots, x_p) = \sum_{j_1 < j_2 < \cdots < j_p} \left( \sum_{\sigma \in S_p} \varepsilon_\sigma \cdot \xi_{j_{\sigma(1)}, 1} \xi_{j_{\sigma(2)}, 2} \cdots \xi_{j_{\sigma(p)}, p} \right) f(e_{j_1}, \ldots, e_{j_p})

where (jk)1≤k≤p(j_k)_{1 \leq k \leq p} runs through the set of strictly increasing sequences of p elements of J.

Now

f(x1,…,xp)=∑(jk)ξj1,1ξj2,2⋯ξjp,pf(ej1,ej2,…,ejp) f(x_1, \ldots, x_p) = \sum_{(j_k)} \xi_{j_1, 1} \xi_{j_2, 2} \cdots \xi_{j_p, p} f(e_{j_1}, e_{j_2}, \ldots, e_{j_p})

where (jk)1≤k≤p(j_k)_{1 \leq k \leq p} runs through all the sequences of p elements of J; it then suffices to apply Corollary 1 to Proposition 7 of § 7, no. 4 to f.

In particular, if J is finite and has n elements and xi=∑j∈Jξjiejx_i = \sum_{j \in J} \xi_{ji} e_j (1≤i≤n)(1 \leq i \leq n) are n elements of M, then

(11)

x1∧x2∧⋯∧xn=(∑σ∈Snεσξjσ(1),1ξjσ(2),2⋯ξjσ(n),n)ej1∧ej2∧⋯∧ejn x_1 \wedge x_2 \wedge \cdots \wedge x_n = \left( \sum_{\sigma \in S_n} \varepsilon_\sigma \xi_{j_{\sigma(1)}, 1} \xi_{j_{\sigma(2)}, 2} \cdots \xi_{j_{\sigma(n)}, n} \right) e_{j_1} \wedge e_{j_2} \wedge \cdots \wedge e_{j_n}

where (jk)1≤k≤n(j_k)_{1 \leq k \leq n} is the unique sequence of the n elements of J arranged in increasing order, whence

(12)

det⁡(x1,x2,…,xn)=∑σ∈Sεσ⋅ξjσ(1),1ξjσ(2),2⋯ξjσ(n),n. \det(x_1, x_2, \ldots, x_n) = \sum_{\sigma \in S} \varepsilon_\sigma \cdot \xi_{j_{\sigma(1)}, 1} \xi_{j_{\sigma(2)}, 2} \cdots \xi_{j_{\sigma(n)}, n}.

With the notation of Lemma 1, comparing formulae (10) and (12) gives

x1∧x2∧⋯∧xp=∑H∈Fp(J)det⁡(xH,1,xH,2,…,xH,p)eH x_1 \wedge x_2 \wedge \cdots \wedge x_p = \sum_{H \in \mathscr{F}_p(J)} \det(x_{H,1}, x_{H,2}, \ldots, x_{H,p}) e_H

where Fp(J)\mathscr{F}_p(J) is the set of subsets of JJ with pp elements and, for every subset H∈Fp(J)H \in \mathscr{F}_p(J), we write xH,i=∑j∈Hξjiejx_{H,i} = \sum_{j \in H} \xi_{ji} e_j and eH=ej1∧ej2∧⋯∧ejpe_H = e_{j_1} \wedge e_{j_2} \wedge \cdots \wedge e_{j_p}, (jk)1≤k≤p(j_k)_{1 \leq k \leq p} being the sequence of elements of HH arranged in increasing order, it being understood that det⁡(xH,1,…,xH,p)\det(x_{H,1}, \ldots, x_{H,p}) is taken with respect to the basis (ejk)1≤k≤p(e_{jk})_{1 \leq k \leq p}.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

Cited by

Nothing.

Cites

Transcribed from the printed edition, 1998, Springer. Not translated.