Bourbaki

Corollary

Tag 0662, permanent. Cite it as [Bourbaki, Tag 0662].

Algebra, chapter III, § 9. Norms and traces

Let A be a commutative K-algebra admitting a finite basis over K and B an A-algebra admitting a finite basis over A. Then B admits a finite basis over K, and, for all b∈Bb \in B ("transitivity formulae")

Tr⁡B/K(b)=Tr⁡A/K(Tr⁡B/A(b)),NB/K(b)=NA/K(NB/A(b))PCB/K(b;X)=NA[X]/K[X](PCB/A(b;X)). \begin{align*} \operatorname{Tr}_{B/K}(b) &= \operatorname{Tr}_{A/K}(\operatorname{Tr}_{B/A}(b)), \quad N_{B/K}(b) = N_{A/K}(N_{B/A}(b)) \\ P_{C_{B/K}}(b; X) &= N_{A[X]/K[X]}(P_{C_{B/A}}(b; X)). \end{align*}
(26) This follows immediately from Proposition 6, setting V=BV = B and u(x)=bxu(x) = bx.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

Cited by

Nothing.

Cites

Transcribed from the printed edition, 1998, Springer. Not translated.