Bourbaki

Example 1

Tag 0669, permanent. Cite it as [Bourbaki, Tag 0669].

Algebra, chapter III, § 10. Derivations

Let A be an R\mathbf{R}-algebra of differentiable mappings of R\mathbf{R} into R\mathbf{R} and let x0x_0 be a point of R\mathbf{R}; R\mathbf{R} can be considered as an A-module with the external law (f,a)↦f(x0)a(f, a) \mapsto f(x_0)a. Then the mapping f↦Df(x0)f \mapsto Df(x_0) is a derivation, since (Functions of a Real Variable, I, § 1, no. 3)

(D(fg))(x0)=(Df(x0))g(x0)+f(x0)(Dg(x0)).∗ (D(fg))(x_0) = (Df(x_0))g(x_0) + f(x_0)(Dg(x_0)).*

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Cites

  • Functions of a Real Variable, I, § 1, no. 3 not yet on this site: FVR I
Transcribed from the printed edition, 1998, Springer. Not translated.