Bourbaki

Example

Tag 067Z, permanent. Cite it as [Bourbaki, Tag 067Z].

Algebra, chapter III, § 11. Cogebras, products of multilinear forms, inner products and duality

(1) Let S be a monoid with identity element u, so that the algebra E=A(S)E = A^{(S)} of the monoid S over A admits the unit element eue_u (§ 2, no. 6); it has been seen on the other hand that E has canonically a coassociative cocommutative A-cogebra structure with a counit γ\gamma such that γ(es)=1\gamma(e_s) = 1 for all s∈Ss \in S (no. 1, Example 4 and no. 2, Examples 4, 5 and 6). The formula c(es)=es⊗esc(e_s) = e_s \otimes e_s giving the coproduct shows also immediately that c is an algebra homomorphism. Thus a cocommutative bigebra structure has been defined on E and E, with this structure, is called the bigebra of the monoid S over A.

If T is another monoid with unit element v, f:S→Tf : S \to T a homomorphism such that f(u)=vf(u) = v and f(A):A(S)→A(T)f_{(A)} : A^{(S)} \to A^{(T)} the A-algebra homomorphism derived from ff (§ 2, no. 6), it is immediately verified that f(A)f_{(A)} is a bigebra homomorphism.

(2) Let M be an A-module. The graded A-algebra (§ 6, no. 1) and graded A-cogebra (no. 1, Example 6) structures defined on S(M) define on this set a commutative cocommutative graded bigebra structure; for we have seen (no. 1, Example 6) that the coproduct on S(M) is an algebra homomorphism and it follows from the definition of the counit γ\gamma (no. 2, Example 6) that γ(1)=1\gamma(1) = 1 and that γ\gamma is an algebra homomorphism of E into A.

(3) Let M be an A-module. We see as in Example 2 that the graded A-algebra (§ 7, no. 1) and graded A-cogebra (no. 1, Example 7) structures on ⋀(M)\bigwedge(M) define on this set an anticommutative anticocommutative skew graded bigebra structure.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Cites

Transcribed from the printed edition, 1998, Springer. Not translated.