Bourbaki

Remark

Tag 0685, permanent. Cite it as [Bourbaki, Tag 0685].

Algebra, chapter III, § 11. Cogebras, products of multilinear forms, inner products and duality

Let MM be an AA-module and ρ:A→B\rho : A \to B a commutative ring homomorphism. Then there is a commutative diagram of graded BB-algebra homomorphisms

T((M∗)(B))⟶(T(M)∗gr)(B)↓T(uM)↓uT(M)T((M(B))∗)→θTT(M(B))∗gr \begin{array}{ccc} T((M^*)_{(B)}) & \longrightarrow & (T(M)^{*gr})_{(B)} \\ \downarrow_{T(u_M)} & & \downarrow^{u_{T(M)}} \\ T((M_{(B)})^*) & \xrightarrow{\theta_T} & T(M_{(B)})^{*gr} \end{array}

where the first row is a homomorphism composed of the homomorphism θT⊗1B:T(M∗)⊗AB→T(M)∗gr\theta_T \otimes 1_B : T(M^*) \otimes_A B \to T(M)^{*gr} and the canonical isomorphism

T((M∗)(B))→T(M∗)⊗AB T((M^*)_{(B)}) \to T(M^*) \otimes_A B

§ 5, no. 3, Proposition 5). It is immediately verified, using formula (28) and the definition of the homomorphism vEv_E (II, § 5, no. 4), that this diagram is commutative. When M is a finitely generated projective A-module, M(B)M_{(B)} is a finitely generated projective B-module (II, § 5, no. 1, Corollary to Proposition 4) and all the homomorphisms of the above diagram are bijective (Proposition 7 and II, § 5, no. 4, Proposition 8). There are analogous commutative diagrams with T replaced by S or Λ\Lambda; the diagram for Λ\Lambda also consists of bijective homomorphisms when M is projective and finitely generated (Proposition 7); if further A is an algebra over Q\mathbf{Q}, the diagram for S also consists of bijective homomorphisms (Proposition 8).

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

Cited by

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Cites

Transcribed from the printed edition, 1998, Springer. Not translated.