Bourbaki

Example

Tag 0687, permanent. Cite it as [Bourbaki, Tag 0687].

Algebra, chapter III, § 11. Cogebras, products of multilinear forms, inner products and duality

In particular the above can be applied when E is one of the graded cogebras T(M), S(M) or Λ(M)\Lambda(M) for an A-module M (no. 1, Examples 5, 6 and 7). To find explicitly the bimodule structures thus obtained, we again identify a homogeneous element f of degree n in T(M)∗grT(M)^{*gr} (resp. S(M)∗grS(M)^{*gr}, resp. Λ(M)∗gr\Lambda(M)^{*gr}) with an n-linear form (resp. symmetric n-linear form, resp. alternating n-linear form, also called an n-form) on MnM^n. It suffices to express the products

(x1⊗x2⊗⋯⊗xp)◃f (resp. (x1x2…xp)◃f, (x_1 \otimes x_2 \otimes \cdots \otimes x_p) \triangleleft f \text{ (resp. } (x_1 x_2 \ldots x_p) \triangleleft f,

resp. (x1∧x2∧⋯∧xp)◃f(x_1 \wedge x_2 \wedge \cdots \wedge x_p) \triangleleft f for every finite sequence (xi)1≤i≤p(x_i)_{1 \leq i \leq p} of elements of M and the analogues for the left inner product. Now, definitions (46) and (52) and formulae (3), (6) and (9) of no. 1 give respectively:

{(x1⊗x2⊗⋯⊗xp)◃f=f▹(x1⊗x2⊗⋯⊗xp)=0(x1x2…xp)◃f=f▹(x1x2…xp)=0for p<n.(x1∧x2∧⋯∧xp)◃f=f▹(x1∧x2∧⋯∧xp)=0 \begin{cases} (x_1 \otimes x_2 \otimes \cdots \otimes x_p) \triangleleft f = f \triangleright (x_1 \otimes x_2 \otimes \cdots \otimes x_p) = 0 \\ (x_1 x_2 \ldots x_p) \triangleleft f = f \triangleright (x_1 x_2 \ldots x_p) = 0 \quad \text{for } p < n. \\ (x_1 \wedge x_2 \wedge \cdots \wedge x_p) \triangleleft f = f \triangleright (x_1 \wedge x_2 \wedge \cdots \wedge x_p) = 0 \end{cases}

For p≥np \geq n, we have respectively

(58) (x1⊗x2⊗⋯⊗xp)◃f=f(x1,…,xn)xn+1⊗⋯⊗xp(x_1 \otimes x_2 \otimes \cdots \otimes x_p) \triangleleft f = f(x_1, \ldots, x_n)x_{n+1} \otimes \cdots \otimes x_p

(59) (x1x2…xp)◃f=∑σf(xσ(1),…,xσ(n))xσ(n+1)⋯xσ(p)(x_1 x_2 \ldots x_p) \triangleleft f = \sum_{\sigma} f(x_{\sigma(1)}, \ldots, x_{\sigma(n)})x_{\sigma(n+1)} \cdots x_{\sigma(p)}

(60) (x1∧x2∧⋯∧xp)◃f=∑σεσf(xσ(1),…,xσ(n))xσ(n+1)∧⋯∧xσ(p)(x_1 \wedge x_2 \wedge \cdots \wedge x_p) \triangleleft f = \sum_{\sigma} \varepsilon_{\sigma} f(x_{\sigma(1)}, \ldots, x_{\sigma(n)})x_{\sigma(n+1)} \wedge \cdots \wedge x_{\sigma(p)}

(where, in (59) and (60), the summations are taken over the permutations σ∈Sp\sigma \in \mathfrak{S}_p which are increasing on each of the intervals [1,n][1, n] and [n+1,p][n+1, p] of N\mathbf{N}; and similarly

(61) f▹(x1⊗x2⊗⋯⊗xp)=f(xp−n+1,…,xp)x1⊗x2⊗⋯⊗xp−nf \triangleright (x_1 \otimes x_2 \otimes \cdots \otimes x_p) = f(x_{p-n+1}, \ldots, x_p)x_1 \otimes x_2 \otimes \cdots \otimes x_{p-n}

(62) f▹(x1x2…xp)=∑σf(xσ(p−n+1),…,xσ(p))xσ(1)⋯xσ(p−n)f \triangleright (x_1 x_2 \ldots x_p) = \sum_{\sigma} f(x_{\sigma(p-n+1)}, \ldots, x_{\sigma(p)})x_{\sigma(1)} \cdots x_{\sigma(p-n)}

(63) f▹(x1∧x2∧⋯∧xp)=∑σεσf(xσ(p−n+1),…,xσ(p))xσ(1)∧⋯∧xσ(p−n)f \triangleright (x_1 \wedge x_2 \wedge \cdots \wedge x_p) = \sum_{\sigma} \varepsilon_{\sigma} f(x_{\sigma(p-n+1)}, \ldots, x_{\sigma(p)})x_{\sigma(1)} \wedge \cdots \wedge x_{\sigma(p-n)}

(where, in (62) and (63), the summations are taken over the permutations σ∈Sp\sigma \in \mathfrak{S}_p which are increasing on each of the intervals [1,p−n][1, p-n] and [p−n+1,p][p-n+1, p] of N\mathbf{N}).

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

Cited by

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Cites

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Transcribed from the printed edition, 1998, Springer. Not translated.