Bourbaki

Corollary 1

Tag 06A1, permanent. Cite it as [Bourbaki, Tag 06A1].

Algebra, chapter IV, § 1. Polynomials

— If A is an integral domain, and u,vu, v are elements of A[(Xi)i∈I]A[(X_i)_{i \in I}], then deg⁡(uv)=deg⁡u+deg⁡v\deg(uv) = \deg u + \deg v.

We can limit ourselves to the case where uu and vv are non-zero. Let m=deg⁡u,n=deg⁡vm = \deg u, n = \deg v; we have

u=u0+u1+⋯+um,v=v0+v1+⋯+vn u = u_0 + u_1 + \cdots + u_m, \quad v = v_0 + v_1 + \cdots + v_n

where uhu_h (resp. vhv_h) is the homogeneous component of degree hh of uu (resp. v). Since um≠0u_m \neq 0 and vn≠0v_n \neq 0, we have umvn≠0u_m v_n \neq 0 (Prop. 8). Now uv=umvn+wuv = u_m v_n + w with deg⁡w<m+n\deg w < m + n, whence the result.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Cites

Transcribed from the printed edition, 2003, Springer. Not translated.