Bourbaki

Proposition 9

Tag 06A3, permanent. Cite it as [Bourbaki, Tag 06A3].

Algebra, chapter IV, § 1. Polynomials

— Let u∈A[(Xi)i∈I]u \in A[(X_i)_{i \in I}]; then for u to be nilpotent in the ring A[(Xi)i∈I]A[(X_i)_{i \in I}] it is necessary and sufficient for all its coefficients to be nilpotent in the ring A.

As in the proof of Prop. 8 we can make a reduction to the case of polynomials in one variable X. If all the coefficients of uu are nilpotent, then uu is nilpotent (I, p. 99, Cor. 1). Suppose that uu is nilpotent but not zero and let nn be its degree; we shall argue by induction on nn. Let aa be the leading coefficient of uu. There exists an integer m>0m > 0 such that um=0u^m = 0. The leading coefficient of umu^m is ama^m, hence am=0a^m = 0. Now u−αXnu - \alpha X^n is nilpotent (I, loc. cit.) and the induction hypothesis shows all the coefficients of u−αXnu - \alpha X^n to be nilpotent. Thus all the coefficients of uu are nilpotent.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

Cited by

Nothing.

Cites

Transcribed from the printed edition, 2003, Springer. Not translated.