Example 4
Tag 06MJ, permanent. Cite it as [Bourbaki, Tag 06MJ].
Algebra, V, p. 58, § 10. Galois extensions
Suppose that is of characteristic and let be the field of rational fractions and . Put and , then the polynomial of has the roots in . Let be the -automorphism of such that . We have and . The group is cyclic of order , and its field of invariants contains ; since , Dedekind's theorem (V, p. 27, Cor. 2) implies that is the field of invariants of and . The polynomial is thus irreducible in ; the extension of is Galois, its Galois group is cyclic of order , and the group is the group of cyclic permutations of .
For a generalization of this example see V, p. 93, Example 2.
Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.
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