— Let (xi)i∈A,(yβ)β∈B be two families of elements of an ordered group G, each having a supremum. Then the family (xα+yβ)(α,β)∈A×B has a supremum, and
(α,β)∈A×Bsup(xα+yβ)=α∈Asupxα+β∈Bsupyβ.
Indeed, from xα+yβ≤z for all α and β, we deduce sup(xi)+sup(yβ)≤z for all β, and hence sup(xi)+sup(yβ)≤z.
1 When A is the ring of integers (resp. the polynomial ring in one indeterminate with coefficients in a field), these definitions coincide with those of I, p. 112 (resp. IV, p. 12, Def. 1).
Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.