Bourbaki

Remark 1

Tag 075K, permanent. Cite it as [Bourbaki, Tag 075K].

Algebra, chapter VII, § 5. Endomorphisms of vector spaces

Clearly the minimal polynomial of the restriction of uu to MpM_p is the greatest power of pp which divides the minimal polynomial of uu. Moreover we have sp(u)⋅x=xs_p(u) \cdot x = x for x∈Mpx \in M_p, from which it follows immediately that, if Mp≠0M_p \neq 0, then sps_p is coprime to pp.

Similarly, by Th. 2 of VII, p. 19, the module EuE_u is isomorphic to a direct sum of cyclic modules Fj=K[X]/aj (1≤j≤r)F_j = K[X]/a_j \ (1 \leq j \leq r), where the ideals aja_j are distinct from K[X]K[X] and aj⊂aj+1a_j \subset a_{j+1}; and the aja_j are determined by these conditions. Moreover, since EE, is a torsion module, we have a1≠(0)a_1 \neq (0); since EE has dimension nn, we have r≤nr \leq n. Put aj=(hj) (1≤j≤r)a_j = (h_j) \ (1 \leq j \leq r), with hjh_j a monic polynomial, and consider the sequence (qi) (1≤i≤n)(q_i) \ (1 \leq i \leq n) of polynomials defined by:

{qi(X)=1if i≤n−rqi(X)=hn−i+1(X)if n−r<i≤n. \begin{cases} q_i(X) = 1 & \text{if } i \leq n - r \\ q_i(X) = h_{n-i+1}(X) & \text{if } n - r < i \leq n . \end{cases}

It is clear that the polynomials qiq_i determine the polynomials hjh_j and conversely, and that EE, is isomorphic to the direct sum of the nn modules K[X]/(qi)K[X]/(q_i), the first n−rn - r of which are 00.

In other words:

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

Cited by

Nothing.

Cites

Transcribed from the printed edition, 2003, Springer. Not translated.