Bourbaki

Theorem 2

Tag 073X, permanent. Cite it as [Bourbaki, Tag 073X].

Algebra, chapter VII, § 4. Finitely generated modules over a principal ideal domain

— Every finitely generated module EE over a principal ideal domain AA is isomorphic to a direct sum of a finite number mm of cyclic modules A/akA/a_k, where the aka_k are ideals of AA (some of which may be zero) such that a1⊂a2⊂…⊂am≠Aa_1 \subset a_2 \subset \ldots \subset a_m \neq A, and which are uniquely determined by these conditions.

If EE can be generated by qq elements then it is isomorphic to a quotient module L/ML/M, where L=AqL = A^q (II. p. 218). Since MM has finite rank n≤qn \leq q (VII, p. 15, Prop. 1), the conditions of Th. 1 (VII, p. 18) are satisfied. Then in the notation of Th. 1 L/ML/M is isomorphic to a direct sum of a complement L′L' of M′M' in LL and the torsion module M′/MM'/M. The module L′L' is free of finite rank p=q−np = q - n, so isomorphic to ApA^p. If rr is the smallest index such that Aαr≠AA\alpha_r \neq A, then M′/MM'/M is isomorphic to the direct sum of modules A/AαiA/A\alpha_i for r≤i≤nr \leq i \leq n. The stated conditions will then be satisfied if we take m=p+(n−r+1)m = p + (n - r + 1), ak=(0)a_k = (0) for 1≤k≤p1 \leq k \leq p, and aj=Aαn,−,a_j = A\alpha_n , - , for 1≤j≤n−r+11 \leq j \leq n - r + 1. Uniqueness follows from the Cor. of VII, p. 16.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Transcribed from the printed edition, 2003, Springer. Not translated.