Bourbaki

Lemma 1

Tag 07A7, permanent. Cite it as [Bourbaki, Tag 07A7].

Topological Vector Spaces, chapter I, § 3. Metrisable topological vector spaces

Let E and F be two topological vector spaces over a non-discrete valued division ring K, and let u be a continuous linear mapping of E in F such that the image of E is not meagre. Then, for every neighbourhood V of 0 in E, the set u(V)‾\overline{u(V)} is a neighbourhood of 0 in F.

Let W be a balanced neighbourhood of 0 in E such that W + W ⊂ V (I, § 1.5, prop. 4). Let α be an element of K such that |α| > 1; then E is the union of the sets αnW\alpha^n W where n varies in N\mathbf{N}; in fact, for all x ∈ E, there exists β ∈ K such that x ∈ βW (I, p. 7, prop. 4) and there exists an integer n ≥ 0 such that |β| < |α|^n, then x ∈ αnW\alpha^n W since W is balanced. Hence, u(E) is the union of the sequence of sets u(αnW)=αnu(W)u(\alpha^n W) = \alpha^n u(W), and as u(E) is not meagre in F, one at least of the sets αnu(W)‾\alpha^n \overline{u(W)} possesses an interior point (GT, IX, § 5.3, def. 2) and therefore u(W)‾\overline{u(W)} has an interior point.

Let y0y_0 be an interior point of u(W)‾\overline{u(W)}; since −u(W)=u(W)-u(W) = u(W), and therefore −u(W)‾=u(W)‾-\overline{u(W)} = \overline{u(W)} it follows that 0=y0+(−y0)0 = y_0 + (-y_0) is an interior point of u(W)‾+u(W)‾\overline{u(W)} + \overline{u(W)}. As vector addition is a continuous mapping of F×FF \times F in FF, the set u(W)‾+u(W)‾\overline{u(W)} + \overline{u(W)} is contained in the closure of the set

u(W)+u(W)=u(W+W)⊂u(V); u(W) + u(W) = u(W + W) \subset u(V);

hence u(V)‾\overline{u(V)} is a neighbourhood of 0 in FF.

Before proving that (iv) implies (i) we prove the following lemma, where we make the convention that, in all metric spaces, Br(x)B_r(x) denotes the closed ball of centre xx and radius rr.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

Cited by

Nothing.

Cites

  • IX, § 5 not yet on this site
  • I, § 1
Transcribed from the printed volume. Not translated.