Bourbaki

Proposition 4 ("logarithmic criterion of order n")

Tag 08F9, permanent. Cite it as [Bourbaki, Tag 08F9].

Functions of a Real Variable, chapter V, § 3. ASYMPTOTIC EXPANSIONS OF FUNCTIONS OF A REAL VARIABLE

Let f be a regulated function ≥0\geq 0 on an interval [a,+∞[[a, +\infty[; if, for some μ>1\mu > 1, f(x)≼1xl1(x)l2(x)…ln−1(x)(ln(x))μf(x) \preccurlyeq \frac{1}{x l_1(x) l_2(x) \ldots l_{n-1}(x) (l_n(x))^\mu}, then the integral ∫a+∞f(t) dt\int_a^{+\infty} f(t) \, dt converges; if f(x)≽1xl1(x)l2(x)…ln−1(x)(ln(x))μf(x) \succcurlyeq \frac{1}{x l_1(x) l_2(x) \ldots l_{n-1}(x) (l_n(x))^\mu} for some μ≤1\mu \leq 1, then the integral ∫a+∞f(t) dt\int_a^{+\infty} f(t) \, dt is infinite.

Each logarithmic criterion is thus applicable to functions for which the criteria of lower order are not decisive (cf. V, p. 264, exerc. 5 b) and V, p. 265, exerc. 8).

Because of its usefulness we translate the criterion of order 0 for integrals ∫αaf(t) dt\int_{\alpha}^{a} f(t) \, dt where ff is regulated and ≥0\geq 0 on a non-compact interval ]α,a]]\alpha, a]:

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

Cited by

Nothing.

Cites

Transcribed from the printed volume. Not translated.